在C中使用epoll,有没有办法从FIFO读取程序来检测写入同一FIFO的程序是否关闭了它?
我认为这会产生一个EPOLLHUP事件,但显然它没有。
实施例: 我有一个读者和一个作家。编写器创建并打开三个FIFO并向它们写入一些浮动并在完成后关闭它们。读者打开FIFO并监视它们,在它们到来时打印浮动,并在作者关闭时关闭FIFO(通过检查EPOLLHUP事件)。这不起作用,读者只是在终止之前保持无限循环。下面的代码,以及我的读者和作者的日志。
读者代码:
#define _XOPEN_SOURCE 700
#include <stdio.h>
#include <stdlib.h>
#include <sys/epoll.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <fcntl.h>
#include <unistd.h>
#include <string.h>
#include <time.h>
#define POLL_TIMEOUT 1000 * 5
struct fifo
{
char *path;
FILE *fp;
int fd;
struct epoll_event ev;
};
#define dbg_fmt(str, ...) {\
time_t curr_time = time(NULL);\
struct tm *curr_tm = gmtime(&curr_time);\
fprintf(stderr, "[%d:%d:%d] "str"\n", curr_tm->tm_hour, curr_tm->tm_min, curr_tm->tm_sec, __VA_ARGS__);\
}
#define dbg(str) {\
time_t curr_time = time(NULL);\
struct tm *curr_tm = gmtime(&curr_time);\
fprintf(stderr, "[%d:%d:%d] %s\n", curr_tm->tm_hour, curr_tm->tm_min, curr_tm->tm_sec, str);\
}
int main(void)
{
int num_fifos = 3;
int num_active_fifos = num_fifos;
struct fifo *fifos = malloc(sizeof(struct fifo) * num_fifos);
int epollfd = epoll_create1(0);
struct epoll_event *epollev = calloc(num_fifos, sizeof(struct epoll_event));
for(int i=0; i<num_fifos; i++)
{
fifos[i].path = malloc(sizeof(char) * strlen("fifoX"));
sprintf(fifos[i].path, "fifo%d", i);
dbg_fmt("opening %s", fifos[i].path);
fifos[i].fp = fopen(fifos[i].path, "r+");
fifos[i].fd = fileno(fifos[i].fp);
fifos[i].ev.data.ptr = (void *)&(fifos[i]);
fifos[i].ev.events = EPOLLIN;
dbg_fmt("registering %s with epoll", fifos[i].path);
epoll_ctl(epollfd, EPOLL_CTL_ADD, fifos[i].fd, &(fifos[i].ev));
}
dbg("entering poll loop");
while(num_active_fifos > 0)
{
dbg("waiting for event...");
int num_events = epoll_wait(epollfd, epollev, num_fifos, POLL_TIMEOUT);\
for(int i=0; i<num_events; i++)
{
struct fifo *curr_fifo = epollev[i].data.ptr;
dbg_fmt("recieved event from %s", curr_fifo->path);
if(epollev[i].events & EPOLLIN)
{
float fl;
fscanf(curr_fifo->fp, "%f", &fl);
dbg_fmt("read %f from %s", fl, curr_fifo->path);
}
if(epollev[i].events & (EPOLLHUP|EPOLLRDHUP|EPOLLERR)) {
dbg_fmt("closing %s", curr_fifo->path);
epoll_ctl(epollfd, EPOLL_CTL_DEL,curr_fifo->fd, NULL);
fclose(curr_fifo->fp);
num_active_fifos--;
}
}
}
for(int i=0; i<num_fifos; i++) {
free(fifos[i].path);
}
close(epollfd);
free(epollev);
free(fifos);
dbg("done");
return 0;
}
作家代码:
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>
#include <stdio.h>
#include <fcntl.h>
#include <time.h>
#include <string.h>
#define dbg_fmt(str, ...) {\
time_t curr_time = time(NULL);\
struct tm *curr_tm = gmtime(&curr_time);\
fprintf(stderr, "[%d:%d:%d] "str"\n", curr_tm->tm_hour, curr_tm->tm_min, curr_tm->tm_sec, __VA_ARGS__);\
}
#define dbg(str) {\
time_t curr_time = time(NULL);\
struct tm *curr_tm = gmtime(&curr_time);\
fprintf(stderr, "[%d:%d:%d] %s\n", curr_tm->tm_hour, curr_tm->tm_min, curr_tm->tm_sec, str);\
}
int main(int argc, char **argv) {
mkfifo("fifo0",0755);
mkfifo("fifo1",0755);
mkfifo("fifo2",0755);
int fifo0 = open("fifo0",O_WRONLY);
int fifo1 = open("fifo1",O_WRONLY);
int fifo2 = open("fifo2",O_WRONLY);
dbg("made FIFOs, sleeping for 5s");
sleep(5);
dbg("writing one value to each fifo (1.2, 0.5, -1.3)");
write(fifo0, "1.2 ", strlen("1.2 "));
write(fifo1, "0.5 ", strlen("0.5 "));
write(fifo2, "-1.3 ", strlen("-1.3 "));
dbg("sleeping for 5s");
sleep(5);
dbg("closing fifo2");
close(fifo2);
dbg("sleeping for 5s");
sleep(5);
dbg("writing two remaining values (-1.0 and 3.2) to fifo1 & closing it");
write(fifo1, "-1.0 ", strlen("-1.0 "));
write(fifo1, "3.2 ", strlen("3.2 "));
close(fifo1);
dbg("sleeping for 5s");
sleep(5);
dbg("server: writing remaining value (-2.5) to fifo0 & closing it");
write(fifo0, "-2.5 ", strlen("-2.5 "));
close(fifo0);
dbg("done");
}
读者日志:
[18:42:3] opening fifo0
[18:42:3] registering fifo0 with epoll
[18:42:3] opening fifo1
[18:42:3] registering fifo1 with epoll
[18:42:3] opening fifo2
[18:42:3] registering fifo2 with epoll
[18:42:3] entering poll loop
[18:42:3] waiting for event...
[18:42:8] waiting for event...
[18:42:11] recieved event from fifo0
[18:42:11] read 1.200000 from fifo0
[18:42:11] waiting for event...
[18:42:11] recieved event from fifo1
[18:42:11] read 0.500000 from fifo1
[18:42:11] recieved event from fifo2
[18:42:11] read -1.300000 from fifo2
[18:42:11] waiting for event...
[18:42:16] waiting for event...
[18:42:21] recieved event from fifo1
[18:42:21] read -1.000000 from fifo1
[18:42:21] waiting for event...
[18:42:26] recieved event from fifo0
[18:42:26] read -2.500000 from fifo0
[18:42:26] waiting for event...
[18:42:31] waiting for event...
[18:42:36] waiting for event...
[18:42:41] waiting for event...
^C
作家日志:
[18:42:6] made FIFOs, sleeping for 5s
[18:42:11] writing one value to each fifo (1.2, 0.5, -1.3)
[18:42:11] sleeping for 5s
[18:42:16] closing fifo2
[18:42:16] sleeping for 5s
[18:42:21] writing two remaining values (-1.0 and 3.2) to fifo1 & closing it
[18:42:21] sleeping for 5s
[18:42:26] server: writing remaining value (-2.5) to fifo0 & closing it
[18:42:26] done
答案 0 :(得分:1)
您的读者需要使用模式fopen
r
FIFO,因为r+
正在阅读和。因此,当编写器关闭所有FIFO时,仍然有读取器,它具有写访问权限,并且不会生成EPOLLHUP信号。