Question

如何在fscanf和$sender_name之后突破线？现在它只显示$sender_number作为输出，但当我删除＆＃34; $sender_name＆＃34;他们都在一条线上。

\n

整个PHP代码

    $body .= chunk_split(base64_encode($sender_name."\n\r"));
    $body .= chunk_split(base64_encode($sender_number."\n\r"));
    $body .= chunk_split(base64_encode($sender_message."\n\r"));

Answer 1

你是base64编码行结尾以及

所以实际输出不会有\ n \ r 试试这个：

$body = $sender_name. "\n";
$body = $sender_number. "\n";
$body = $sender_message. "\n";

编辑：鉴于您的代码：

.=

在这些行中，您不会附加字符串，而是为其指定新值;使用HashSet<string>代替赋值运算符

Answer 2

你也是encondig“\ n \ r”，请务必将换行符放在最后，

  $body .= chunk_split(base64_encode($sender_name)) . PHP_EOL;
  $body .= chunk_split(base64_encode($sender_number)) . PHP_EOL;
  $body .= chunk_split(base64_encode($sender_message)) . PHP_EOL;

如果您使用PHP_EOL发送电子邮件作为html替换<br />，请执行以下操作：

  $body .= chunk_split(base64_encode($sender_name)) . "<br />";
  $body .= chunk_split(base64_encode($sender_number)) . "<br />";
  $body .= chunk_split(base64_encode($sender_message)) . "<br />";

PHP断线＆＃34;。\ n＆＃34;没有在电子邮件正文中工作。线条消失了

2 个答案: