Question

所以我正在制作一个快速骰子滚轮（用于D＆amp; D），当我尝试掷骰子时，它只生成1到4的数字！

import random


def d4():
    x = (random.randint(1,4))
    print(x)

def d6():
    x = (random.randint(1,6))
    print(x)

def d8():
    x = (random.randint(1,8))
    print(x)

def d10():
    x = (random.randint(1,10))
    print(x)

def d12():
    x = (random.randint(1,12))
    print(x)

def d20():
    x = (random.randint(1,20))
    print(x)

def d100():
    x = (random.randint(1,100))
    print(x)


choice = input("What dice will you roll: ")


if choice == "d4" or "4":
    d4()
elif choice == "d6" or "6":
    d6()
elif choice == "d8" or "8":
    d8()
elif choice == "d10" or "10":
    d10()
elif choice == "d12" or "12":
    d12()
elif choice == "d20" or "20":
    d20()
elif choice == "d100" or "100":
    d100()
else:
    print(random.randint(1,20))

例如，当我将输入设为d100时，我只能获得1,2,3或4！到底是怎么回事？！

Answer 1

你的if语句不正确，它们应该是这样的：

if choice == "d4" or choice == "4":
    d4()

你做的方式使得＆＃34; 4＆＃34;评估为True，因此if总是进入第一个语句，即D4。

random.randint生成错误的数字

1 个答案: