Question

PHPer第一次寻求帮助。

<?php
DEFINE ('DB_USER', 'hiddenforsecurity');
DEFINE ('DB_PSWD', 'hiddenforsecurity');
DEFINE ('DB_HOST', 'hiddenforsecurity');
DEFINE ('DB_NAME', 'hiddenforsecurity');

    $email = $_POST['email'];
    $password = $_POST['password'];

    if($email && $password){
      $dbcon = mysqli_connect(DB_HOST, DB_USER, DB_PSWD, DB_NAME) or die("cant connect");

      $query = mysql_query("SELECT * FROM users WHERE email='$email'");

      $numrows = mysql_num_rows($query);

      if($numrows != 0){
        echo "Account Located";
      } else {
          die("that user doesn't exist");
      }
    } else {
      die("Please enter an email and a password.");
    }
 ?>

这是我的HTML表单：

 <form method="POST" action="login.php">
  <div class="form-group">
    <label>Email address</label>
    <input type="email" name="email" class="form-control" id="exampleInputEmail1" aria-describedby="emailHelp" placeholder="Enter email">
  </div>
  <div class="form-group">
    <label>Password</label>
    <input type="password" name="password" class="form-control password" id="exampleInputPassword1" placeholder="Password">
  </div>
  <button type="submit" class="btn btn-primary">Submit</button>
</form>

当我在输入中没有任何内容时按下提交时，我收到PHP中指定的错误（“请输入电子邮件和密码”）。当我提交我手动放入数据库的电子邮件和密码的测试值时，Chrome告诉我localhost无法处理此请求，http错误500.我确定这只是一个新手错误，非常感谢任何帮助。谢谢！

其他信息：我在MAMP上运行PHP。

Answer 1

你混淆了mysqli和mysql函数，因此可能导致500错误

PHP登录脚本在提交时服务500错误

1 个答案: