将' AggregateRating'一个'服务'在Google SERP中显示星级评分?

时间:2018-01-13 10:30:55

标签: schema.org google-rich-snippets

以下代码会在Google中显示SERP结果的星级吗?

<div itemscope itemtype="http://schema.org/Service">
                            Horoscope 2018          </span>
            Overall rating:         <span itemprop="aggregateRating" itemscope itemtype="http://schema.org/AggregateRating">
                <strong><span class="value" itemprop="ratingValue">
                    4.7             </span></strong> out of
                <strong><span itemprop="bestRating">5</span></strong> based on
                <span class="votes" itemprop="reviewCount">
                    26              </span> reviews.
            </span>
        </div>

1 个答案:

答案 0 :(得分:0)

我在代码的第二行添加了一个缺失的开始dburl = "jdbc:mysql://localhost:3306/dbname?useServerPrepStmts=false&rewriteBatchedStatements=true&useUnicode=true&characterEncoding=utf8&useJDBCCompliantTimezoneShift=true&useLegacyDatetimeCode=false&serverTimezone=UTC&useSSL=false" 标记,并在Google Structured Data Testing Tool上进行了验证,因此我认为有理由认为它符合条件在Google SERP结果中显示。

符合条件并不能保证它会显示,Google也会考虑其他因素。

祝你好运!
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