如何在django中编写联接,我已经阅读了下面的django文档,但是联接对我的模型不起作用
http://docs.djangoproject.com/en/1.2/topics/db/queries/#lookups-that-span-relationships
和models / many_to_many /
和一些博客
我的模特:
class Profile(models.Model):
name = models.CharField(max_length=50, primary_key=True)
assign = models.CharField(max_length=50)
doj = models.DateField()
dob = models.DateField()
class Meta:
db_table = u'profile'
def __str__(self):
return '%s %s %s %s' % ( self.name,self.assign,self.doj,self.dob)
def __unicode__(self):
return u'%s %s %s %s' % ( self.name,self.assign,self.doj,self.dob)
enter code here
class working(models.Model):
w_name =models.ForeignKey(Profile, db_column='w_name')
monday = models.IntegerField(null=True, db_column='monday', blank=True)
tuesday = models.IntegerField(null=True, db_column='tuesday', blank=True)
wednesday = models.IntegerField(null=True, db_column='wednesday', blank=True)
class Meta:
db_table = u'working'
def __str__(self):
return '%s %s %s %s' % ( self.w_name,self.monday,self.tuesday,self.wednesday)
def __unicode__(self):
return u'%s %s %s %s' % ( self.w_name,self.monday,self.tuesday,self.wednesday)
我正在尝试在两个表profile和workingday之间进行连接
like m=working.objects.filter(name='sushanth').select_related()
如果我在查询之上运行,我会得到
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/usr/lib/pymodules/python2.6/django/db/models/manager.py", line 129, in filter
return self.get_query_set().filter(*args, **kwargs)
File "/usr/lib/pymodules/python2.6/django/db/models/query.py", line 498, in filter
return self._filter_or_exclude(False, *args, **kwargs)
File "/usr/lib/pymodules/python2.6/django/db/models/query.py", line 516, in _filter_or_exclude
clone.query.add_q(Q(*args, **kwargs))
File "/usr/lib/pymodules/python2.6/django/db/models/sql/query.py", line 1675, in add_q
can_reuse=used_aliases)
File "/usr/lib/pymodules/python2.6/django/db/models/sql/query.py", line 1569, in add_filter
negate=negate, process_extras=process_extras)
File "/usr/lib/pymodules/python2.6/django/db/models/sql/query.py", line 1737, in setup_joins
"Choices are: %s" % (name, ", ".join(names)))
FieldError: Cannot resolve keyword 'name' into field. Choices are: monday, tuesday, wednesday, w_name
我需要查询我可以加入工作和个人资料的位置。
支持
select working.*,profile.assign,profile.doj from working join profile where name=w_name ;
我知道django不支持加入,内连接也适合我。
任何人都可以帮助.........................?
答案 0 :(得分:4)
请格式化您的问题,以便代码可读({}图标),否则很难阅读。
working.objects.filter(name=
将失败,因为您的working
模型没有name
字段。
来自您关联的文档:
Django提供强大而直观的功能 “跟随”关系的方式 查找,处理SQL JOIN 为你自动,在后面 场景。只是为了跨越关系 使用相关字段的字段名称 跨模型,以double分隔 下划线,直到你到达 你想要的领域。
转换为:
m = working.objects.filter(w_name__name='sushanth').select_related()