Python中出现意外的缩进错误,即使没有缩进

时间:2018-01-13 08:19:47

标签: python

当我运行此代码时,我得到一个意外的缩进错误,但没有缩进,它说有。我正在使用python 64位和Python 3.我尝试了unindenting所有代码并重新发送它但我得到了同样的错误。我正在尝试创建一个用户可以注册并登录的GUI。

以下是代码:

from tkinter import *
import json
import hashlib
import uuid
from tkinter import messagebox
filename = ("username.json")
filename2 = ("password.json")

def hash_password(password):
    # uuid is used to generate a random number
    salt = uuid.uuid4().hex
    return hashlib.sha256(salt.encode() + password.encode()).hexdigest() + ':' + salt

def check_password(hashed_password, user_password):
    password, salt = hashed_password.split(':')
    return password == hashlib.sha256(salt.encode() + user_password.encode()).hexdigest()

def sign_up():
    adduser = (e3.get())
    addpassword = (e4.get())

    try:
        hashed_password = hash_password(addpassword)
        with open (filename, "w") as f_obj:
            json.dump(adduser, f_obj)

        with open (filename2, "w") as f:
            json.dump(hashed_password, f)
        #print("Signed up")
        messagebox.showinfo("Info", "You have succesfully signed up!")

def log_in():
    try:
        with open (filename) as f_obj:
        data = json.load(f_obj)
    except FileNotFoundError :
        usernameguess = (e1.get())
        passwordguess = (e2.get())
        user_attempt = usernameguess
        pwd_attempt = passwordguess
        with open (filename) as f_obj:
            username = json.load(f_obj)
        if username == user_attempt:
            with open (filename2) as f:
            password = json.load(f)
            if check_password(password, pwd_attempt):
                print("You're into your account")
            else:
                print("Incorrect password")
        else:
            print("Incorrect username")


master = Tk()

master.geometry("390x220")
master.iconbitmap('favicon.ico')
master.title("Account Manager : Log In | Sign Up")
Label(master, text="Welcome to the Account Manager \n Sign up or Log in \n Note: Your password is protected by hash encryption").grid(row=0, column=1)
Label(master, text="Log In").grid(row=1, column=1)
Label(master, text="Username").grid(row=2)
Label(master, text="Password").grid(row=3)

Label(master, text="Sign Up").grid(row=5, column=1)
Label(master, text="Username").grid(row=6)
Label(master, text="Password").grid(row=7)


e1 = Entry(master)
e2 = Entry(master)
e3 = Entry(master)
e4 = Entry(master)

e1.grid(row=2, column=1)
e2.grid(row=3, column=1)
e3.grid(row=6, column=1)
e4.grid(row=7, column=1)


Button(master, text='Quit', command=master.quit).grid(row=9, column=0, sticky=W, pady=4)
Button(master, text='Sign Up', command=sign_up).grid(row=8, column=1, sticky=W, pady=4)
Button(master, text='Log In', command=log_in).grid(row=4, column=1, sticky=W, pady=4)


mainloop( )

1 个答案:

答案 0 :(得分:3)

错误不一样,但在上一行!

在函数sign_up()log_in()函数之前的函数)中,有try但不是except:

def sign_up():
    adduser = (e3.get())
    addpassword = (e4.get())

    try:
        hashed_password = hash_password(addpassword)
        with open (filename, "w") as f_obj:
            json.dump(adduser, f_obj)

        with open (filename2, "w") as f:
            json.dump(hashed_password, f)
        #print("Signed up")
        messagebox.showinfo("Info", "You have succesfully signed up!")

def log_in():
    try:
        with open (filename) as f_obj:
        ...

Python期望缩进except:语句。因此,错误。

此代码中也存在其他真正的缩进错误,一旦纠正此错误,这些错误就会变得明显。

也许Python应该提供"missing except" error而不是"indent" error