以下是我导入的内容:
import React, { Component } from 'react'
import {
Image,
Text,
TextInput,
Keyboard,
KeyboardAvoidingView,
TouchableOpacity,
View,
Linking,
AsyncStorage,
Alert
} from 'react-native'
这是设置状态的函数(从下面的TextInput调用)
setName = (name, value) => {
AsyncStorage.setItem(name, value);
}
以下是它的调用方式
<TextInput
keyboardType='default'
autoCapitalize='words'
returnKeyType='next'
onSubmitEditing={() => this.lastNamedRef.focus()}
underlineColorAndroid='transparent'
style={{flex:1}}
placeholder='Your first name'
value={this.state.firstName}
onChangeText={(text) => [this.validateInputLength(text, 2, 50, 'firstName'), this.setName('firstName', this.state.firstName)]}
/>
<TextInput
keyboardType='default'
autoCapitalize='words'
returnKeyType='done'
ref={lastNameRef => this.lastNamedRef = lastNameRef}
underlineColorAndroid='transparent'
style={{flex:1}}
placeholder='Your last name'
value={this.state.lastName}
onChangeText={(text) => [this.validateInputLength(text, 2, 50, 'lastName'), this.setName('lastName', this.state.lastName)]}
/>
如果我从TextInput中的onChangeText中删除this.setName()函数,该应用程序不会崩溃,但是当它在那里时,它会在iOS上崩溃,但不会在Android上崩溃。当使用setName函数更新componentWillMount()(下面)时,this.state.firstName和this.state.lastName来自AsyncStorage
componentWillMount() {
AsyncStorage.getItem('firstName').then((value) => this.setState({firstName:value}))
AsyncStorage.getItem('lastName').then((value) => this.setState({lastName:value}))
}
componentWillMount()中的AsyncStorage.getItem不会使应用程序崩溃,但似乎不会将数据加载到字段中。大多数时候它会加载,但不是每次都加载。 AsyncStorage一般看起来超级越野车。
这是validateInputLength函数
validateInputLength = (text, min=10, max=25, type) => {
if(text.length < min || text.length > max) {
if(type=='firstName') {
this.setState({firstName:text})
this.setState({firstNameValidated:false})
return false;
} else if (type=='lastName') {
this.setState({lastName:text})
this.setState({lastNameValidated:false})
return false;
}
} else {
if(type=='firstName') {
this.setState({firstName:text})
this.setState({firstNameValidated:true})
} else if (type=='lastName') {
this.setState({lastName:text})
this.setState({lastNameValidated:true})
}
}
}
......这里是构造函数
constructor(props) {
super(props)
this.state = {
firstName: '',
lastName: '',
firstNameValidated: false,
lastNameValidated: false,
};
}
这会在iOS上崩溃,无论是在我的iPhone上还是在模拟器中运行,都没有显示任何错误。有任何想法吗?
答案 0 :(得分:1)
如果您尝试存储JSON对象以进行例如expo崩溃,则只能在AsyncStorage中存储字符串,这可能是发生的事情,在存储对象之前尝试使用JSON.stringify