Question

如何获取以下代码以返回所需的输出。这只是一个主要的简单csharp，没有ASP.NET。

//Desired output: <amp>Before & After</amp>

//instead of

//Current output: <amp>Before &amp; After</amp>

    static void Main(string[] args)
    {
        string amp = "Before & After";
        XmlDocument doc = new XmlDocument();

        StringBuilder sb = new StringBuilder();
        StringWriter stringWriter = new StringWriter(sb);
        XmlTextWriter xmlWriter = new XmlTextWriter(stringWriter);

        xmlWriter.WriteStartElement("amp");
        xmlWriter.WriteString(amp);
        xmlWriter.WriteEndElement();

        global::System.Windows.Forms.MessageBox.Show(sb.ToString());
    }

以下是我解决特定问题的方法。

        string amp = "Before & After";
        XmlDocument doc = new XmlDocument();

        StringBuilder sb = new StringBuilder();
        StringWriter stringWriter = new StringWriter(sb);
        XmlTextWriter xmlWriter = new XmlTextWriter(stringWriter);

        xmlWriter.WriteStartElement("amp");
        xmlWriter.WriteString(amp);
        xmlWriter.WriteEndElement();

        StringReader valueStringReader = new StringReader(sb.ToString());
        XmlTextReader valueXmlReader = new XmlTextReader(valueStringReader);

        valueXmlReader.MoveToContent();

        global::System.Windows.Forms.MessageBox.Show(valueXmlReader.ReadString());

Answer 1

如果您想要无效的XML，请自行创建。

        string amp = "Before & After";

        // don't really do this, it's very wrong
        StringBuilder sb = new StringBuilder();
        sb.Append("<amp>");
        sb.Append(amp);
        sb.Append("</amp>");

        Console.WriteLine(sb);

但这是 NOT 有效的xml，所以不要这样做。如果要使用XML，则需要使用有效的XML。您的原始代码示例是正确的。

如果你想要更具人性化的东西，那就不要使用XML，使用YAML。

http://www.yaml.org/

amp: Before & After

Answer 2

所需的输出不是有效的XML。当前输出与CDATA部分相同，Before & After和<![CDATA[Before & After]]>只是两种不同的转义＆符号的方式，因此您可以拥有有效的XML。在任何一种情况下，如果您使用任何XML解析器来阅读<amp>标记的内容，它将返回Before & After。

Answer 3

您可以将文字放入CDataSection - 请参阅XmlDocument.CreateCDataSection。

Answer 4

以下是我解决特定问题的方法。

        string amp = "Before & After";
        XmlDocument doc = new XmlDocument();

        StringBuilder sb = new StringBuilder();
        StringWriter stringWriter = new StringWriter(sb);
        XmlTextWriter xmlWriter = new XmlTextWriter(stringWriter);

        xmlWriter.WriteStartElement("amp");
        xmlWriter.WriteString(amp);
        xmlWriter.WriteEndElement();

        StringReader valueStringReader = new StringReader(sb.ToString());
        XmlTextReader valueXmlReader = new XmlTextReader(valueStringReader);

        valueXmlReader.MoveToContent();

        global::System.Windows.Forms.MessageBox.Show(valueXmlReader.ReadString());

解码＆amp;来自＆amp;来自XML的ToString（）

4 个答案: