Question

我想知道是否有一种不同的更短的方式来打印列表中的特定值，而不必多次重复打印（num [x]，num [x]，num [x]）

num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]

print(num[5])
print(num[5], num[12])

Answer 1

像这样循环：

for i in [5, 12]:
   print(num[i], end=' ')

Answer 2

您可以使用operator.itemgetter：

>>> from operator import itemgetter
>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> itemgetter(5, 12)(num)
('5', 'c')

Answer 3

您可以使用列表理解：

>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> print( [num[x] for x in (5, 12)] )
['5', 'c']

Answer 4

您可以简单地定义一个功能。

def getVal(List, *index):
    for x in index:
        print(List[x], end=" ")

 num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
 getVal(num, 1, 5, 3)

 # 1 5 3

Answer 5

您只需map()即可：

>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> list(map(lambda x: num[x], [5, 12]))
['5', 'c']

Answer 6

你需要一个功能：

num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]

def index_no(first,second):
    try:
        return (num[first],num[second])
    except IndexError:
        pass

print(index_no(5,12))

输出：

('5', 'c')

从Python 3中的列表中打印特定值

6 个答案: