我有复杂的类,我想使用costum属性序列化为XML格式。我被困在XMLelement这是List,我想用构造函数生成新项目,我可以在其中填充属性名称和文本值。
现在我必须创建单独的对象以及我可以添加到List中的对象。我想简化这个。
要序列化的类:
[XmlElement("Cfg")]
public ElCfg Cfg = new ElCfg();
public class ElCfg
{
[XmlAttribute("Name")] public string CfgName { get; set; } = "Default";
[XmlElement("Content")] public ElCont Content = new ElCont();
}
public class ElCont
{
[XmlAttribute("ver")] public string ContentVer { get; set; }
[XmlElement("Prop")] public List<ElProp> Properties = new List<ElProp>();
}
public class ElProp
{
[XmlAttribute("Name")]
public string PropertyName { get; set; }
[XmlText]
public string PropertyVal { get; set; }
}
在main中的用法:
static void Main(string[] args)
{
//build promotic object
PromoticXML xmlDoc = new PromoticXML();
xmlDoc.Cfg.Content.ContentVer = "80323";
PromoticXML.ElProp prop1 = new PromoticXML.ElProp();
prop1.PropertyName = "neco";
prop1.PropertyVal = "necojineho";
PromoticXML.ElProp prop2 = new PromoticXML.ElProp();
prop2.PropertyName = "neco";
prop2.PropertyVal = "necojineho";
xmlDoc.Cfg.Content.Properties.Add(prop1);
xmlDoc.Cfg.Content.Properties.Add(prop2);
//serialize promotic object
XmlWriterSettings xmlSet = new XmlWriterSettings();
xmlSet.Encoding = Encoding.Unicode;
xmlSet.Indent = true;
xmlSet.IndentChars = " ";
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
XmlSerializer serializer = new XmlSerializer(typeof(PromoticXML));
using (XmlWriter writer = XmlWriter.Create("promotic.xml", xmlSet))
{
serializer.Serialize(writer, xmlDoc);
}
Process.Start("notepad.exe", "promotic.xml");
}
我的目标是:
xmlDoc.Cfg.Content.Properties.Add(new PromoticXML.ElProp("someName", "someText"));
而不是:
PromoticXML.ElProp prop1 = new PromoticXML.ElProp();
prop1.PropertyName = "neco";
prop1.PropertyVal = "necojineho";
xmlDoc.Cfg.Content.Properties.Add(prop1);