Question

我正在使用python。我有一个文本文件，格式如下：

###########
text lines
###########
text lines
###########
text lines
###########

我想为两个＆＃34; ######＆＃34;之间找到的每个段运行一个算法。线。如何引用两个＆＃34; ######＆＃34;之间的文本行。线。两个＆＃34; ######＆＃34;之间的行数。线不固定。

感谢

Answer 1

您可以使用split()轻松完成此操作：

with open('myfile.txt') as f:
    data = f.read().split('###########')
    print([txt.strip() for txt in data if txt])

Answer 2

这会有用吗？

f = open("textfile.txt")
for line in f.readlines():
   if '######' not in line:
       print(line) # evaluate and process the line here

Answer 3

或者这个怎么样：

with open("f.txt") as f:
    print(''.join(x for x in filter(lambda x: x != '###########', f.read().split("\n"))))

Answer 4

file.txt：

###########
line1
#
line2
######
line3
line4
line5
##########
line6
line7

代码：

import re

FILE_PATH = "file.txt"

blocks = []
lines = []

with open(FILE_PATH) as file:
    for line in file:
        if re.fullmatch(r"#+(\n){0,1}", line):
            if lines:
                blocks.append(lines)
                lines = []
        else:
            lines.append(line.rstrip("\n"))  # remove rstrip if you want to keep a new line at the end of a line

# store last block (if file does not end with #+ line)
if lines:
    blocks.append(lines)

print(blocks)  # [['line1'], ['line2'], ['line3', 'line4', 'line5'], ['line6', 'line7']]

Answer 5

考虑“######”不包含“\ n”：

def get_chunks(filename):
    with open(filename) as f:
        return f.read().split('#'*6)[2:-1:2]

否则：

import re

def get_chunks(filename):
    with open(filename) as f:
        return re.split(r'(#\n?){6}', f.read())[4:-1:4]

隔离并使用文本文件中的某些行

5 个答案: