我正在使用config.php文件来表示类似的东西,我试图将我的mysql凭据放在那里然后在不同的文件中使用它们,但它没有传递值,
是否有任何可以帮助我找到解决方案。
code config.php:
/* Database credentials*/
$dbHost = 'localhost';
$dbName = 'xx';
$dbUsername = 'xx';
$dbWachtwoord = 'xx';
代码dbconnect.php:
<?php include 'config.php';
class Database
{
private $host;
private $db_name;
private $username;
private $password;
public $conn;
public function dbConnection()
{
$this->host = $dbHost;
$this->db_name = $dbName;
$this->username = $dbUsername;
$this->password = $dbWachtwoord;
$this->conn = null;
try
{
$this->conn = new PDO("mysql:host=" . $this->host . ";dbname=" . $this->db_name, $this->username, $this->password);
$this->conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $exception)
{
echo "Connection error: " . $exception->getMessage();
}
return $this->conn;
}
}
Class.user dbconnection:
<?php
require_once('config.php');
require_once('dbconnect.php');
class USER
{
private $conn;
public function __construct()
{
$database = new Database();
$db = $database->dbConnection();
$this->conn = $db;
}
public function runQuery($sql)
{
$stmt = $this->conn->prepare($sql);
return $stmt;
}
提前致谢=)
答案 0 :(得分:2)
不要将其视为传递变量,而应将其视为传递配置。您的Database类必须知道这些配置选项才能使用它。换句话说:一旦你创建了一个类Database的实例,它应该被配置并准备好使用,就像任何服务一样。 我强烈建议您遵循injecting the configuration as a dependency的规则。
答案 1 :(得分:1)
在您的课程中加入'config.php
public function dbConnection()
{
include 'config.php';
$this->host = $dbHost;
$this->db_name = $dbName;
$this->username = $dbUsername;
$this->password = $dbWachtwoord;
$this->conn = null;
try
{
答案 2 :(得分:0)
您可以尝试以下代码:
<强>的config.php 强>
<?php
return [
'dbHost' => 'localhost',
'dbName' => 'xx',
'dbUsername' => 'xx',
'dbWachtwoord' => 'xx',
];
用户类
class USER
{
private $conn;
private $config;
public function __construct()
{
$this->config = include "config.php";
$database = new Database(this->config['dbHost'], $this->config['dbUsername'], $this->config['dbWachtwoord'], $this->config['dbName']);
//...
}
//...
}
<强> dbconnect.php 强>
public function dbConnection($dbHost, $dbName, $dbWachtwoord, $dbName)
{
//....
}