如何将文件下载到本地目录

时间:2018-01-12 09:16:15

标签: python download python-requests urllib3

如何将python中的文件下载到本地目录C:\ 1 \ 1。我看到很多例子,但大多数似乎都是5岁以上,有过时的信息。感谢。

 import urllib.request

url = "http://download.thinkbroadband.com/10MB.zip"

file_name = url.split('/')[-1]
u = urllib.request.urlretrieve.urlopen(url)
f = open(file_name, 'wb')
meta = u.info()
file_size = int(meta.getheaders("Content-Length")[0])
print("Downloading: %s Bytes: %s" % (file_name, file_size))

file_size_dl = 0
block_sz = 8192
while True:
    buffer = u.read(block_sz)
    if not buffer:
        break

    file_size_dl += len(buffer)
    f.write(buffer)
    status = r"%10d  [%3.2f%%]" % (file_size_dl, file_size_dl * 100. / file_size)
    status = status + chr(8)*(len(status)+1)
    print(status,)

f.close()

错误:函数没有打开属性url

AttributeError: 'function' object has no attribute 'urlopen'

有人可以向我解释我如何从网站上下载一个简单的zip,这对我不起作用。欢呼声。

1 个答案:

答案 0 :(得分:0)

import requests

url = "http://download.thinkbroadband.com/10MB.zip"
src = r"C:\1\1\downloaded_zip.zip"


respo = requests.get(url, stream=True, verify=False)
if respo.status_code == requests.codes.ok:
    out = open(src, "wb")
    for block in respo.iter_content(1024):
        if not block:
            break

        out.write(block)

    out.close()
else:
    print("Not able to download ZIP url {url}: {status}, {content}".format(url=url, status=respo.status_code, content=respo.content))