Question

所以基本上文本文件看起来像这样

Starting Cash: 1500
Turn Limit (-1 for no turn limit): 10
Number of Players Left To End Game: 1
Property Set Multiplier: 2
Number of Houses Before Hotels: 4
Must Build Houses Evenly: Yes
Put Money In Free Parking: No
Auction Properties: No
Salary Multiplier For Landing On Go: 1

我需要的所有文件基本上都是“：”之后的任何内容我只是混淆了如何在“：”之后只阅读任何内容？这就是我现在所拥有的。我似乎无法想到只扫描数字/ yesorno的方法。

void readRules(char*file_name)
{
  Rules r;
  FILE *file = NULL;
  file = fopen(file_name, "r");

  if (file == NULL) {
    printf("Could not open %s\n", file_name);
    return;
  }
  char c=fgetc(file);
  fscanf(file, "%c", &c);
  while (!feof(file))
  {
    fscanf(file, "%c", &c);
    if(c==':')
    {
      r.startCash=c;
    }
  }

  printf("There are %c word(s).\n", r.startCash);

  fclose(file);
}

谢谢。

Answer 1

该程序将读取给定文件的每一行冒号后的整数。我想这个合适吗？冒号后还有一些字符串。如果你想阅读那些，你可以尝试扫描字符串“％s”并测试函数是否返回非零（至少匹配一种格式模式）。

#include <stdio.h>
#include <stdlib.h>

#define MAXLINE     1000

void readRules (const char *filename) {
    FILE *fp;
    char *lp, line[MAXLINE];
    int n;

    // Return early if file cannot be opened.
    if ((fp = fopen(filename, "r")) == NULL) {
        fprintf(stderr, "Error: Couldn't open \"%s\"!\n", filename);
        return;
    }

    // Use fgets to read consecutive lines. Returns NULL on error or EOF.
    while (fgets(line, MAXLINE, fp) != NULL) {

        // Read until newline is hit or buffer size exceeded.
        for (lp = line; *lp != '\n' && (lp - line) < MAXLINE; lp++) {

            // If encounter colon and sccanf reads at least 1 integer..
            if (*lp == ':' && sscanf(lp + 1, "%d", &n) == 1) {
                fprintf(stdout, "%d\n", n);
                break;
            }
        }
    }


    // Clean up.
    fclose(fp);
}

int main (int argc, const char *argv[]) {
    readRules("test.txt");
    return 0;
}

使用示例输入运行时，它会生成：

C：如何读取文本文件并在某一点后获取某些值？

1 个答案: