Question

我无法在这里找出错误的位置。据我所知，一切看起来都是正确的：

SELECT  a.department_name
FROM department a
OUTER JOIN (SELECT department_id, 
            NVL((TO_CHAR(MAX(salary + commission)), '$9,990.00'), '$0.00') as "Maximum Total Pay",
            NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Maximum Hire Date",
            NVL((TO_CHAR(MIN(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Minimum Hire Date",
            COUNT(*) AS NUMBER_OF_EMPLOYEES
            FROM employee c
            WHERE employee_id IS NOT NULL
            GROUP BY c.department_id)
ON          a.department_id = c.department_id  
ORDER BY    a.department_name;

我收到SQL命令未正确结束的错误。任何帮助将不胜感激。

谢谢！

编辑：我无法选择两个正确的答案，因为这些都有助于我找到正确的解决方案。感谢所有帮助过的人。

Answer 1

我想，空值可能来自您的子查询，但不是来自部门，因此请使用LEFT OUTER JOIN。

但主要问题是由于对

的禁忌

NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000')陈述，

两种用途：

NVL(TO_CHAR(MAX(hire_date), 'DD-MON-YYYY'), '01-JAN-3000')取而代之的是，从左侧删除第1和第5个paranthesis。

Answer 2

您似乎需要为要加入的子查询设置别名，并添加关键字{1, 2, 3, 4}：

LEFT

我将其称为SELECT a.department_name FROM department a LEFT OUTER JOIN (SELECT department_id, NVL((TO_CHAR(MAX(salary + commission)), '$9,990.00'), '$0.00') as "Maximum Total Pay", NVL((TO_CHAR(MAX(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Maximum Hire Date", NVL((TO_CHAR(MIN(hire_date)), 'DD-MON-YYYY'), '01-JAN-3000') as "Minimum Hire Date", COUNT(*) AS NUMBER_OF_EMPLOYEES FROM employee c WHERE employee_id IS NOT NULL GROUP BY c.department_id) c1 ON a.department_id = c1.department_id ORDER BY a.department_name;，以便您可以注意到别名。

我的SQL命令没有正确结束

2 个答案: