Python中数字的十进制部分

Question

我有以下程序

def F_inf(a,b):
    x1=a.numerator/a.denominator
    x2=b.numerator/b.denominator

        if x1<x2:
            print "a<b"
    elif x1>x2:
        print "a>b"
    else: print "a=b" 

a=Fraction(10,4)
b=Fraction(10,4)

F_inf(a, b)

当我执行它时，x1只接收分数的整数值，例如，如果我必须计算2/4 x1等于0而不是0.5。 我该怎么办 ？ 感谢

Answer 1

听起来你正在使用Python2。最好的解决方案是切换到Python 3（不仅仅是因为划分而是因为"Python 2.x is legacy, Python 3.x is the present and future of the language"）。

除此之外，你还有几个选择。

from __future__ import division
# include ^ as the first line in your file to use float division by default

或

a = 1
b = 2
c = a / (1.0*b) # multiplying by 1.0 forces the right side of the division to be a float
#c == 0.5 here