Question

我有两个列表，我尝试根据Group =＆gt;加入ID和艺术家=＆gt;群ID。

当我展示群组时，我想要从艺术家列表中显示群组中的所有成员。

            var groupID = from Group in allGroups
                          join Artist in allArtists
                          on Group.Id equals Artist.GroupId
                          into Members
                          where Group.Id == id
                          select new
                          {
                              Group = Group.GroupName,
                              Members
                          };
            return Json(groupID);

当JSON数据在浏览器中呈现时，我从每个艺术家那里获得所有数据，我只想显示名称。见下文：

[{＆＃34;组＆＃34;：＆＃34; G-单元＆＃34;＆＃34;会员＆＃34;：[{＆＃34; ARTISTNAME＆＃34;：＆＃34;劳埃德Banks＆＃34;，＆＃34; realName＆＃34;：＆＃34; Christopher Lloyd＆＃34;，＆＃34; age＆＃34;：34，＆＃34; hometown＆＃34;：＆＃34;纽约City＆＃34;，＆＃34; groupId＆＃34;：2，＆＃34; group＆＃34;：null}，{＆＃34; artistName＆＃34;：＆＃34; The Game＆＃34;，＆＃ 34; realName＆＃34;：＆＃34; Jayceon Taylor＆＃34;，＆＃34; age＆＃34;：37，＆＃34; hometown＆＃34;：＆＃34; Compton＆＃34;，＆＃34; groupId＆＃34;：2，＆＃34; group＆＃34;：null}，{＆＃34; artistName＆＃34;：＆＃34; 50 Cent＆＃34;，＆＃34; realName＆＃34;：＆＃ 34; Curtis Jackson＆＃34;，＆＃34; age＆＃34;：41，＆＃34; hometown＆＃34;：＆＃34;纽约市＆＃34;，＆＃34; groupId＆＃34;：2，＆＃34;组＆＃34;：空}]}]

提前感谢您的帮助！

Answer 1

这应该有用......

var groupID = from Group in allGroups
                      join Artist in allArtists
                      on Group.Id equals Artist.GroupId
                      into Members
                      where Group.Id == id
                      select new
                      {
                          Group = Group.GroupName,
                          Members = Members.Select(e => e.artistName)
                      };
        return Json(groupID);

如何从我分组到列表中的对象集合中获取单个属性？

1 个答案: