Question

我有不同属性的顶点。现在我想过滤掉具有特定属性值的那些。以下是我的代码的样子：

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现在我想过滤顶点，属性为// Different property classes for different vertex class VertexProperty() case class Property1(val name: String, val servings: Int) extends VertexProperty case class Property2(val description: String) extends VertexProperty case class Property3(val name: String, val quantity: Double, val measurementUnit: String) extends VertexProperty val vertexArray = Array( (1L, Property1("propertyName",8)), (2L, Property2("property description")), (3L, Property3("", 1,"lb.")) ) val edgeArray = Array( Edge(1L, 2L, "step1"), Edge(1L, 3L, "step2") ) val vertexRDD: RDD[(Long, VertexProperty)] = sc.parallelize(vertexArray) val edgeRDD: RDD[Edge[String]] = sc.parallelize(edgeArray) val graph: Graph[VertexProperty, String] = Graph(vertexRDD, edgeRDD)且其描述不为空，我尝试过以下方式：

它没有给出预期的结果
```
Property2
```

此代码无效

graph.vertices.filter { case (id, (descrition)) => descrition !="" }.foreach{
  case (id, (descrition)) => println(s"$descrition")
}

Answer 1

您尝试过的代码很接近但不完全正确。 filter中需要两个案例;一个用于Property2，一个用于所有其他情况。

val vertices = graph.vertices.filter{
  case (id, vp: Property2) => vp.description != ""
  case _ => false
}

这将为您提供一个VertexRDD[VertexProperty]，其中包含满足要求的所有顶点。

Graphx Scala：在具有属性继承的Vertex上应用过滤器

1 个答案: