Question

我想验证列表以确保没有重复的项目。我的问题是我在if语句中不知道如何做到这一点。如果列表中有重复项，python中是否有一个方法或其他东西会返回False？

以下是我的想法：

lst = ["1","2","3","3","4"]

if #lst contains no duplicates :
    print("success")
else:
    print("duplicate found")

提前致谢。

Answer 1

正如Jkdc所说，将其转换为集合并比较长度

lst = ["1","2","3","3","4"]

if len(set(lst)) == len(lst):
    print("success")
else:
    print("duplicate found")

Answer 2

利用Python has_duplicate()可能不包含重复项的事实。 def has_duplicates(listObj): return len(listObj) != len(set(listObj)) print(has_duplicates([1, 2, 1, 1, 4, 7])) ## PRINTS: True print(has_duplicates([9, 2, 5, 4, 7])) ## PRINTS: False函数负责确定列表是否包含重复项。

ts_fin <- ts(emea$Value, deltat = 1/24, start = c(2014, 21))

Answer 3

检查这个，最简单的方法（至少对我而言）..

lst = ["1","2","3","3","4"]
status = True
for item in lst:
    if lst.count(item) > 1:
      # the count functions counts how many times the "item" is in lst
        status = False

if status == True:
    print("No duplicates")
else:
    print("Duplicates found")

Answer 4

def check_duplicates(lst):
    seen = {}
    for item in lst:
        if seen.get(item):
            print("duplicate found")
            return
        else:
            seen[item] = True
    print("success")

Answer 5

def checkDuplicate():
    count = {}
    for item in lst:
            if item not in count:
                count[item] = 1
            else:
                return True
    return False

如何检查列表是否包含重复项？

5 个答案: