Question

我有三种不同的字符串数组：

var firstArrayString: [String] = ["01:00", "02:00", "03:00"]
var secondArrayString: [String] = ["04:00", "05:00", "06:00"]
var thirdArrayString: [String] = ["07:00", "08:00", "09:00", "10:00"]

我对每个字符串数组 价格：

var priceFirst: Int = 1000
var priceSecond: Int = 1500
var priceThird: Int = 2000

我使用 collectionCell 来显示我所有的数组字符串。

override func viewDidLoad() {
    super.viewDidLoad()

    var allArrayStrings: [String] = firstArrayString + secondArrayString + thirdArrayString

}

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {

    return allTimeintervalArray.count

}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {

    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as! BookingTimeCell

    cell.timeLabel.text = allTimeintervalArray[indexPath.item]

    // how can I display different prices in each of the rows of the array?

}

我想在 collectionCell ：

中大致显示

01:00 - 1000
02:00 - 1000
03:00 - 1000
04:00 - 1500
05:00 - 1500
06:00 - 1500
07:00 - 2000
08:00 - 2000
09:00 - 2000
10:00 - 2000

我该如何展示？

我尝试了很多 if 和切换的组合，但没有任何帮助，也许我写错了。请帮帮我。

Answer 1

另一种方法是创建元组数组（价格和字符串值）：

let allArrayStringsAndPrices: [(price: Int, value: String)] =
    firstArrayString.map({ (price: priceFirst, value: $0) })
    + secondArrayString.map({ (price: priceSecond, value: $0) })
    + thirdArrayString.map({ (price: priceThird, value: $0) })

并使用它：

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
    return allArrayStringsAndPrices.count
}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as! BookingTimeCell
    cell.timeLabel.text = "\(allArrayStringsAndPrices[indexPath.row].value) - \(allArrayStringsAndPrices[indexPath.row].price)"
    return cell
}

Answer 2

您可以使用包含时间间隔及其各自价格的元组String数组，而不是使用(String, String)数组，即

var firstArrayString: [(String, String)] = [("01:00", 1000), ("02:00", 1000), ("03:00", 1000)]
var secondArrayString: [(String, String)] = [("04:00", 1500), ("05:00", 1500), ("06:00", 1500)]
var thirdArrayString: [(String, String)] = [("07:00", 2000), ("08:00", 2000), ("09:00", 2000), ("10:00", 2000)]

然后在collection view中，您可以像以下一样使用它：

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell
{
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as! BookingTimeCell
    cell.timeLabel.text = allTimeintervalArray[indexPath.item].0
    cell.priceLabel.text = allTimeintervalArray[indexPath.item].1
}

Answer 3

如果您将集合视图分成几个部分（本例中为三个），每个数组一个，那么您将会感到很不舒服。

var allArrayStrings = [[String]]()
var allPrices = [Int]()

override func viewDidLoad() {
    super.viewDidLoad()

    allArrayStrings = [firstArrayString, secondArrayString, thirdArrayString]
    allPrices = [priceFirst, priceSecond, priceThird]
}

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
    return allArrayStrings.count
}

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
    return allArrayStrings[section].count
}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as! BookingTimeCell

    cell.timeLabel.text = "\(allArrayStrings[indexPath.section][indexPath.item]) - \(allPrices[indexPath.section])"

    return cell
}

Answer 4

您可以在打印单元格中使用if语句进行数组计数：

override func viewDidLoad() {
    super.viewDidLoad()

}

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {

    return firstArrayString.count + secondArrayString.count + thirdArrayString.count

}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {

    let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as! BookingTimeCell

    if indexPath.item < firstArrayString.count {
        cell.timeLabel.text = "\(firstArrayString[indexPath.item]) - \(priceFirst)"
    }    
    else if indexPath.item < (firstArrayString.count + secondArrayString.count) {
        cell.timeLabel.text = "\(secondArrayString[indexPath.item - firstArrayString.count]) - \(priceSecond)"
    } 
    else {
        cell.timeLabel.text = "\(thirdArrayString[indexPath.item - firstArrayString.count - secondArrayString.count]) - \(priceThird)"
    } 

}

Answer 5

Swift 4

我认为这可以为少量数据提供帮助。

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {

    guard let cell = collectionView.dequeueReusableCell(withReuseIdentifier: "timeCell", for: indexPath) as? BookingTimeCell else { return UICollectionViewCell() }

    let currentString = allTimeintervalArray[indexPath.item]

    if firstArray.contains(currentString) {
        print("Current Array Value:", currentString, "And Price :", firstPrice)
    } else if secondArray.contains(currentString) {
        print("Current Array Value:", currentString, "And Price :", secondPrice)
    } else if thirdArray.contains(currentString) {
        print("Current Array Value:", currentString, "And Price :", thirdPrice)
    } else {
        print("None of the arrays contain", currentString)
    }
}

在数组的每个项目中显示不同的价格

5 个答案: