Question

我有像JSON一样的

string fields = "{'foo':'{\'Resources\':{\'resourceUri\':\'/xf/b/rs/RA-a-675e/fo/age/s/m78\',\'location\':\'us\',\'tags\':{\'displayName\':\'A's storage\',\'container.registry\':\'dd\'}}}'}";

不幸的是，我无法更改JSON以上

var customDict = JsonConvert.DeserializeObject<Dictionary<string, string>>(fields);

始终抛出异常。为什么呢？

Answer 1

这个JSON不仅仅是一个简单的Dictionary<string, string>！它是一种自定义类型，如下所示：

JSON：

{foo:{Resources:{resourceUri:"/xf/b/rs/RA-a-675e/fo/age/s/m78",location:"us",tags:{displayName:"As storage",containerregistry:"dd"}}}}

C＃类：

public class Tags
{
    public string displayName { get; set; }
    public string containerregistry { get; set; }
}

public class Resources
{
    public string resourceUri { get; set; }
    public string location { get; set; }
    public Tags tags { get; set; }
}

public class Foo
{
    public Resources Resources { get; set; }
}

public class Example
{
    public Foo foo { get; set; }
}

之后你可以反序列化：

var customObject = JsonConvert.DeserializeObject<Foo>(fields);

Answer 2

如果要将此JSON字符串解析为Dictionary<string, string>，则可以将每个\替换为\\，并将A's storage替换为A\\'s storage。替换后，输入字符串变为如下：

string fields = "{'foo':'{\\'Resources\\':{\\'resourceUri\\':\\'/xf/b/rs/RA-a-675e/fo/age/s/m78\\',\\'location\\':\\'us\\',\\'tags\\':{\\'displayName\\':\\'A\\'s storage\\',\\'container.registry\\':\\'dd\\'}}}'}";

然后当你打电话：

var customDict = JsonConvert.DeserializeObject<Dictionary<string, string>>(fields);

customDict只包含一个键值对：

customDict["foo"] == "{'Resources':{'resourceUri':'/xf/b/rs/RA-a-675e/fo/age/s/m78','location':'us','tags':{'displayName':'A's storage','container.registry':'dd'}}}"

Answer 3

我不知道为什么你的json字符串出了问题。无论如何，我认为这是你固定的json字符串

IWebElement

为您的项目安装string jsonString = "{'foo':{'Resources':{'resourceUri':'/xf/b/rs/RA-a-675e/fo/age/s/m78','location':'us','tags':{'displayName':'As storage','containerregistry':'dd'}}}}"; Manage Nuget Packages，然后将这些Newtonsoft.Json类用于您的json字符串

POCO

现在您可以将json字符串反序列化为C＃对象

public class Rootobject
{
    public Foo foo { get; set; }
}

public class Foo
{
    public Resources Resources { get; set; }
}

public class Resources
{
    public string resourceUri { get; set; }
    public string location { get; set; }
    public Tags tags { get; set; }
}

public class Tags
{
    public string displayName { get; set; }
    public string containerregistry { get; set; }
}

这是一个完整的控制台应用程序示例

var deserializedRootObject = Newtonsoft.Json.JsonConvert.DeserializeObject<Rootobject>(jsonString);

System.Console.WriteLine(deserializedRootObject.foo.Resources.location); // us

如何使用C＃

3 个答案: