Question

尝试访问类UploadModal中的方法，方法被调用但是 _file

的错误

export class UploadModal {
   @ViewChild(NgFileSelect) _file: NgFileSelect;

  // this method is called
  calledMethod(event, fileType) { 

  const name: string = this._file.uploader._queue[0].name; // getting this._file undefined

}

export class ImageComponent {   // other class in which I need to only use methods in class UploadModal
    callingMethod($event, fileType) {
        let uploadModal = new UploadModal();
        uploadModal.calledMethod($event, fileType);
    }
}

Answer 1

您需要在名为<?xml version="1.0"?> <z-Component z-type="ActionBar" z-base="Page" z-namespace="UI.Pages" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="./../.zebble-schema.xml"> <Stack Style.Margin.Top="10" Style.Margin.Left="5"> <Drawing> <Drawing.Line></Drawing.Line> </Drawing> </Stack> </z-Component>的生命周期钩子中通过var __drawing_Line1 = new Drawing.Line { Id = "__drawing_Line1" };获取孩子。在这个循环中，您的视图已准备好，它可以让孩子。

来自Documentation

在调用ngAfterViewInit回调之前设置视图查询。

ViewChild

Answer 2

试试这个代码段

export class ImageComponent {   
    componentRef: UploadModal;
    constructor(){ this.componentRef = new UploadModal(); }
    callingMethod($event, fileType) {
        this.componentRef.calledMethod($event, fileType);
    }
}

访问'B'组件中'A'的视图

2 个答案: