Question

我有这个sql代码已经执行了计数

SELECT COUNT(*) as total FROM a_children c 
LEFT JOIN recipient r ON c.hp_id = r.hp_id 
WHERE c.FIRST_HEALTH='OKU' 
AND c.hp_id = r.hp_id
 UNION ALL 
SELECT COUNT(*) 
FROM recipient 
WHERE DISABILITY = "YES"

我得到

的结果

total|
------
52   |
53   |

如何在最终结果中将这2个总数合并为一个

total|
------
105  |

Answer 1

您可以将其用作派生表，然后使用Sum。

   Select sum(total) sumofTotal from
   (SELECT COUNT(*) as total FROM a_children c 
    LEFT JOIN recipient r ON c.hp_id = r.hp_id 
    WHERE c.FIRST_HEALTH='OKU' 
    AND c.hp_id = r.hp_id
     UNION ALL 
    SELECT COUNT(*) 
    FROM recipient 
    WHERE DISABILITY = 'YES'
   ) x

Answer 2

您可以使用CTE。

;with cte as(
SELECT COUNT(*) as total FROM a_children c 
LEFT JOIN recipient r ON c.hp_id = r.hp_id 
WHERE c.FIRST_HEALTH='OKU' 
AND c.hp_id = r.hp_id
 UNION ALL 
SELECT COUNT(*) 
FROM recipient 
WHERE DISABILITY = "YES"

)select sum(total) as total from cte

Answer 3

最简单的方法是子查询：

select sum(total)
from (SELECT COUNT(*) as total
      FROM a_children c LEFT JOIN
           recipient r
           ON c.hp_id = r.hp_id 
      WHERE c.FIRST_HEALTH = 'OKU' AND c.hp_id = r.hp_id
      UNION ALL 
      SELECT COUNT(*) 
      FROM recipient 
      WHERE DISABILITY = 'YES'
     ) x;

可能只是简单地进行查询 - 完全摆脱union。但如果没有更好地了解表格的外观，就很难提出具体的建议。

Answer 4

试试这个查询！

SELECT    count(sum)  AS  total 
    FROM
        (    SELECT count(*)   AS sum 
             FROM a_children c 
             LEFT JOIN recipient r ON c.hp_id = r.hp_id 
             WHERE c.FIRST_HEALTH='OKU' 
             AND c.hp_id = r.hp_id
          UNION ALL 
             SELECT count(*)  AS sum
             FROM recipient 
             WHERE DISABILITY = "YES"
        )

用于组合两个计数的sql代码

4 个答案: