Question

代码

var q = JSON.parse('[{"15": {"bUrl": "https://example.com/r2359","name": "Ninpo","url": null,"desc": null,"series": [{"title": "Nana","id": "6308","authors": ["Author1"]}]}}, {"390": {"bUrl": "https://example.com/r2667","name": "Sanpo","url": null,"desc": null,"series": [{"title": "Baba","id": "6498","authors": ["Author2"]}]}}]');

var yy = [];
for (i = 0; i < q.length; i++) {
    yy.push(q[i]);
}
console.log(yy);

我试图访问字符串＆＃34; 15＆＃34;和＆＃34; 390＆＃34;，但循环遍历它们只是给我每个组的整个对象。我如何只提取数字字符串，以便我可以用它们构建数组？

Answer 1

您可以在对象上使用Object.keys将密钥作为数组获取，并使用Array#reduce和Array#concat的组合将密钥平面映射到单个数组中。

var q = JSON.parse('[{"15": {"bUrl": "https://example.com/r2359","name": "Ninpo","url": null,"desc": null,"series": [{"title": "Nana","id": "6308","authors": ["Author1"]}]}}, {"390": {"bUrl": "https://example.com/r2667","name": "Sanpo","url": null,"desc": null,"series": [{"title": "Baba","id": "6498","authors": ["Author2"]}]}}]');

console.log(
  Object.keys(q[0])
)

console.log(
  q.reduce((acc, x) => acc.concat(Object.keys(x)), [])
)

<script src="https://codepen.io/synthet1c/pen/KyQQmL.js"></script>

如何使用入门键从JSON对象构建数组？

1 个答案: