当满足if语句时,弹出一个模态

时间:2018-01-10 09:59:48

标签: php if-statement

我希望在满足if语句后弹出模态弹出窗口。以下是代码示例:

<form action="" method="post">
<button type="submit" name="btn">Test</button>
</form>

<?php
 if (isset($_POST['btn'])) {
//then trigger the modal pop-up
}
?>

1 个答案:

答案 0 :(得分:2)

如果你想要打开模态窗口,那么你必须使用javascript / jquery,如下所示

<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>

<form action="" method="post">
<button type="submit" name="btn">Test</button>
</form>

<?php if (isset($_POST['btn'])) { ?>

<script>
$(function() {
$("#myModal").modal();//if you want you can have a timeout to hide the window after x seconds
});
</script>

<!-- Modal -->
  <div class="modal fade" id="myModal" role="dialog">
    <div class="modal-dialog">

      <!-- Modal content-->
      <div class="modal-content">
        <div class="modal-header">
          <button type="button" class="close" data-dismiss="modal">&times;</button>
          <h4 class="modal-title">Modal Header</h4>
        </div>
        <div class="modal-body">
          <p>Sample modal window</p>
        </div>
        <div class="modal-footer">
          <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
        </div>
      </div>

    </div>
  </div>

<?php } ?>