Question

这是我的控制器代码：

 public function save(Request $request) {
    try {

        $this->validate($request, Country::rules());


        If(Input::hasFile('flag_image')){
            $file = Input::file('flag_image');
            $destinationPath = public_path(). '/images/admin/country/';
            $filename = $file->getClientOriginalName();
            $image = time().$filename;
            $file->move($destinationPath, $image);
            $imgpath = 'public/images/admin/country/'.$image;
        }
        $request['flag_image'] = $imgpath;
        $country = Country::saveOrUpdate($request);
        if($country !== false) {
            return redirect()->route('lists-country')->with('success', trans('Country data added successfully.!!'));
        } else {
            return back()->with('error', "Unable to save country data.!!")->withInput();
        }
    } catch (\Exception $ex) {
        return back()->with('error', "Unable to save country data.!!")->withInput();
    }
}

当我在dd($request)功能之前saveOrUpdate时，我获得了图片上传文件的完整路径。

 +request: ParameterBag {#40 ▼
#parameters: array:6 [▼
  "_token" => "c94UG3R2PbbdHsXRLzs9OjEBTna23OHINFpki63U"
  "id" => ""
  "title" => "INDIA"
  "short_name" => "IN"
  "status" => "Active"
  "flag_image" => "public/images/admin/country/1515577652banner5.jpg"
]}

在表格上成功添加数据后，flag_image路径看起来像"D:\xampp\tmp\php63D3.tmp"我希望存储"public/images/admin/country/1515577652banner5.jpg"此路径。

Answer 1

只做

$country->flag_image = $imgpath;
$country->save();

之后

$country = Country::saveOrUpdate($request);

Answer 2

您需要merge()：

$request->merge(['flag_image' => $imgpath]);

而不是：

$request['flag_image'] = $imgpath;

laravel：如何将文件上传的路径存储在数据库中

2 个答案: