我是一个初学者,我正在尝试为一个课程创建一个程序,该程序将通过一个关于某些结果的数据集。我遇到了以下JSON中的所有团队的困难:
{
"name": "English Premier League 2014/15",
"rounds": [
{
"name": "Matchday 1",
"matches": [
{
"date": "2014-08-16",
"team1": {
"key": "manutd",
"name": "Manchester United",
"code": "MUN"
},
"team2": {
"key": "swansea",
"name": "Swansea",
"code": "SWA"
},
"score1": 1,
"score2": 2
},
{
"date": "2014-08-16",
"team1": {
"key": "leicester",
"name": "Leicester City",
"code": "LEI"
},
"team2": {
"key": "everton",
"name": "Everton",
"code": "EVE"
},
"score1": 2,
"score2": 2
}],
}],
}
我使用了这些代码行:
for matchday in js['rounds'] :
print(matchday['matches'][0]['team1']['name'])
这将打印每轮第一场比赛中第一支球队的名字,但我想打印每一轮所有第一支球队的名字。有人能给我一个暗示吗?
答案 0 :(得分:3)
你应该添加第二个循环并迭代匹配:
for rounds in js['rounds']:
for matches in rounds['matches']:
print(matches['team1']['name'])
答案 1 :(得分:0)
你正在获取匹配列表中的第一项,只需再循环遍历列表,如
for matchday in js['rounds'] :
match_day = matchday['matches']
for each_match in match_day:
print(each_match['team1']['name'])
答案 2 :(得分:0)
for json_data in data['rounds']:
for attribute, value in json_data.iteritems():
print attribute, value