我试图从单行获取数据,我得到了这个错误。
mysql_fetch_row() expects parameter 1 to be resource,
这是我的代码:
$message = "SELECT b_message FROM site_setting WHERE id = '1'";
$resultmessage = mysqli_query($conn, $message);
$row = mysql_fetch_row($resultmessage);
echo $row[0];
需要帮助
答案 0 :(得分:0)
尝试使用mysqli_fetch_row()
$row = mysqli_fetch_row($resultmessage);
echo $row[0];
答案 1 :(得分:0)
$b_message=array();
$message = "SELECT b_message FROM site_setting WHERE id = '1'";
$resultmessage = mysqli_query($conn, $message);
while($row = $resultmessage->fetch_assoc());
{
$b_message[]=$row['b_message'];
}
print_r($b_message);