Question

我想在不使用GET方法的情况下检索在url中传递的值即 http://example.com?id=10 而是使用这样的东西 http://example.com/10

Answer 1

您可以在php

示例： -

import { Component, OnInit, ViewChild } from '@angular/core';
import { SortService, ResizeService, GroupService, ColumnMenuService, PageService, FilterService } from '@syncfusion/ej2-ng-grids';
import { ContextMenuItem, GroupSettingsModel, FilterSettingsModel, EditSettingsModel, ColumnMenuItemModel } from '@syncfusion/ej2-ng-grids';
import { GridComponent } from '@syncfusion/ej2-ng-grids';
import { MenuEventArgs } from '@syncfusion/ej2-navigations';
import { data } from './data';

@Component({
    selector: 'control-content',
    templateUrl: 'columnmenu.html',

})
export class ColumnMenuComponent implements OnInit {
    public data: Object[];
    public groupOptions: GroupSettingsModel;
    public filterSettings: FilterSettingsModel;
    public columnMenuItems: ColumnMenuItemModel[];
    @ViewChild('grid')
    public grid: GridComponent;

    ngOnInit(): void {
        this.data = data.slice(0, 60);
        this.groupOptions = { showGroupedColumn: true };
        this.filterSettings = { type: 'checkbox' };
        this.columnMenuItems = [{text:'Clear Sorting', id:'gridclearsorting'}];
    }

    public columnMenuClick(args: MenuEventArgs): void {
    console.log('123');
      if(args.item.id === 'gridclearsorting'){
            this.grid.clearSorting();
        }
    }
}

Answer 2

如果您想在不使用10方法的情况下从网址获取GET。

//get complete url
$url = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
//using explode function convert into array
$url = explode('/', $url);
//print your desired array index
echo $url[2];

Answer 3

JavaScript本身没有内置处理查询字符串参数的内容。

在（现代）浏览器中，您可以使用（写作时的实验）URL对象;

var url_string = "http://www.example.com/t.html?a=1&b=3&c=m2-m3-m4-m5"; //window.location.href
var url = new URL(url_string);
var c = url.searchParams.get("c");
console.log(c);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

运行代码snippetCopy代码段以answerExpand代码段对于较旧的浏览器，您可以使用此polyfill或此答案的原始版本中的代码，该代码早于URL：

你可以访问location.search，它可以从你那里获得？字符串到URL的末尾或片段标识符的开头（#foo），以先到者为准。

通过Quentin回答 How to get the value from the GET parameters?

Answer 4

如果是PHP

$uri = explode('/', $_SERVER['REQUEST_URI']);
print_r($uri); #  Array ( [0] => http: [1] => [2] => example.com [3] => 10 )
echo $uri[3]; # 10

如何在不使用GET方法的情况下从网址获取数据

4 个答案:

您可以在php