MYSQL查询中的多个Select语句

Question

我有一张mysql表，用于在不同的市场上销售产品。

Date   Marketplace   Sale 
1      flipkart       1000
1      flipkart       500
1      amazon          200
1      amazon         1500
1      amazon          700
2      myntra          500
2      flipkart       1000

我想要一个单独的mysql声明，它可以让我在不同的市场（亚马逊，flipkart等）上进行一个月的明确销售，就像这种情况一样 在

第1个月的flipkart毛销量为1500（1000 + 500），亚马逊毛销售2400（1500 + 700 + 200）

我有这个问题：

SELECT  date, (Select sum(gross_sale) from sku where marketplace='flipkart') as flipkart, (Select sum(gross_sale) from sku where marketplace='Myntra') as myntra, sum(gross_sale) as countdate FROM sku WHERE   date >= '2017-11-01' AND
        date   <= '2017-11-30' GROUP BY date ORDER BY date ASC limit 30 ;

但是，选择子查询并没有给出日期分配，而是总月销售额。如何解决这个问题。请帮忙。提前谢谢。

Answer 1

Mysql为您提供sum()并按任务分组。您可以通过以下查询

检索所需的结果

select Date, Marketplace, sum(Sale) from table group by Date, Marketplace

sum()将在group by

的帮助下汇总同一市场的所有价格

发表评论后

如果您不想使用循环，并且您需要查询单个结果，那么您只需要where子句

select Date, Marketplace, sum(Sale) from table where Marketplace = 'flipkart'

Answer 2

试试这个：

SELECT Date,Marketplace, SUM(Sale) 
FROM tab111 where date =1
Group By Marketplace 

Answer 3

你有没有尝试过工会：

select date,marketplace,sum(sales) from yourtable where marketplace='flipkart'

union

select date,marketplace,sum(sales) from yourtable where marketplace='amazon'

这是sqlfiddle

Answer 4

试试这个

SELECT 
    sk.date,
    sum(sk1.sale) as flipkart_sum_sale,
    sum(sk2.sale) as amanzon_sum_sale
FROM
    sku sk
        LEFT JOIN
    sku sk1 ON sk.id = sk1.id
        AND sk1.marketplace = 'flipkart'
        LEFT JOIN
    sku sk2 ON sk.id = sk2.id
        AND sk2.marketplace = 'amazon'
GROUP BY sk.date;

Answer 5

select Date,Marketplace, sum(Sale) from table group by Marketplace;