假设有这样的清单
l = ['1\xa0My Cll to Adventure: 1949–1967',
'2\xa0Crossing the Threshold: 1967–1979',
'3\xa0My Abyss: 1979–1982',
'4\xa0My Rod of Trils: 1983–1994',
'5\xa0The Ultimte Boon: 1995–21',
'6\xa0Returning the Boon: 211–215',
'7\xa0My Lst Yer nd My Gretest Chllenge: 216–217',
'8\xa0Looking Bck from Higher Level']
我想要的结果是
[' 1.My Cll to Adventure: 1949–1967',
' 2.Crossing the Threshold: 1967–1979',
' 3.My Abyss: 1979–1982',
' 4.My Rod of Trils: 1983–1994',
' 5.The Ultimte Boon: 1995–21',
' 6.Returning the Boon: 211–215',
' 7.My Lst Yer nd My Gretest Chllenge: 216–217',
' 8.Looking Bck from Higher Level']
我尝试使用代码
import re
In [114]: [re.sub(r'\d\xa0', r' \d.', i) for i in l]
Out[114]:
[' \\d.My Cll to Adventure: 1949–1967',
' \\d.Crossing the Threshold: 1967–1979',
' \\d.My Abyss: 1979–1982',
' \\d.My Rod of Trils: 1983–1994',
' \\d.The Ultimte Boon: 1995–21',
' \\d.Returning the Boon: 211–215',
' \\d.My Lst Yer nd My Gretest Chllenge: 216–217',
' \\d.Looking Bck from Higher Level']
它无法按照我的意图用数字代替。
如何完成这项任务?
答案 0 :(得分:2)
在完全停止之前,您无法捕获所需的数字。要做到这一点,我们只需要在我们想要捕获的数字周围使用括号,然后使用它们的捕获组ID引用它们,即1
。
使用:
l = ['1\xa0My Cll to Adventure: 1949–1967',
'2\xa0Crossing the Threshold: 1967–1979',
'3\xa0My Abyss: 1979–1982',
'4\xa0My Rod of Trils: 1983–1994',
'5\xa0The Ultimte Boon: 1995–21',
'6\xa0Returning the Boon: 211–215',
'7\xa0My Lst Yer nd My Gretest Chllenge: 216–217',
'8\xa0Looking Bck from Higher Level']
然后我们运行:
import re
[re.sub(r'(\d+)\xa0', r' \1.', i) for i in l]
并获得输出:
[' 1.My Cll to Adventure: 1949–1967',
' 2.Crossing the Threshold: 1967–1979',
' 3.My Abyss: 1979–1982',
' 4.My Rod of Trils: 1983–1994',
' 5.The Ultimte Boon: 1995–21',
' 6.Returning the Boon: 211–215',
' 7.My Lst Yer nd My Gretest Chllenge: 216–217',
' 8.Looking Bck from Higher Level']
答案 1 :(得分:1)
以下工作在string
循环中使用replace
for
方法:
outl = []
for i in l:
outl.append(" "+i.replace("\xa0",".",1))
print(outl)
输出:
[' 1.My Cll to Adventure: 1949–1967',
' 2.Crossing the Threshold: 1967–1979',
' 3.My Abyss: 1979–1982',
' 4.My Rod of Trils: 1983–1994',
' 5.The Ultimte Boon: 1995–21',
' 6.Returning the Boon: 211–215',
' 7.My Lst Yer nd My Gretest Chllenge: 216–217',
' 8.Looking Bck from Higher Level']