Question

import time
from threading import Timer
from random import randint
print("Every wrong answer is a 3s delay; you have 30s")
end = False
def lose():
    print(end)
    print("Time up!")
    time.sleep(1)
    print("Score is",pts,", with",wrong,"wrong answers.")
    time.sleep(1)
    input("enter to quit")
    quit()
timer = Timer(10,lose)
timer.start()
pts = 0
wrong = 0
while end == False:
    a = randint(5,50)
    b = randint(5,50)
    print(a,"+",b)
    ans = input()
    if ans.isnumeric():
        ans = int(ans)
    if ans == a+b:
        print("correct")
        pts = pts+1
    else:
        print("wrong,",a+b)
        wrong = wrong+1
        print("delay")
        time.sleep(3)
        print("delay end")
    print("")

当计时器结束时，循环重叠'输出'功能，它就像这样混乱：

Time up!

45 + 10
55
Score iscorrect 
3 
, with29  0+  wrong answers.37


enter to quitwrong,p
 66
delay

如何解决此问题？
对不起，如果这个问题已经得到解答，但我想知道。

Answer 1

理想情况下，您应该完全避免使用线程，如评论中所述。

但是，如果要使用线程，请考虑使用mutex来确保多个线程不会同时尝试写入stdout。

例如：

# setup at the beginning:
from threading import Thread, Lock
mutex = Lock()

# surrounding each print statement:
mutex.acquire()
try:
    print('text')
finally:
    mutex.release()

我正在测试threading.Time在我制作的这个小游戏中，但它不断重叠

1 个答案: