Question

我需要为调度程序导入特殊格式的文本文件，因为时间压力非常高，我决定寻求帮助并在将来更好地学习它。文件格式如下所示：

2 0 1 3 5 4 t 1 3 6 7 3 6   
1 2 4 5 0 3 t 8 5 10 10 10 4   
2 3 5 0 1 4 t 5 4 8 9 1 7   
1 0 2 3 4 5 t 5 5 5 3 8 9   
2 1 4 5 0 3 t 9 3 5 4 3 1  
1 3 5 0 4 2 t 3 3 9 10 4 1

每一行代表一项活动，t代表工人的数字和t代表工人后的数字。

到目前为止，我发现它看起来应该是这样的：

public static List<ArrayList<WorkUnit>> readInputFile(String fileName)
        throws IOException {

    InputStream inputStream;
    if (fileName.equals("/textfile.txt"))
        inputStream = Util.class.getResourceAsStream(fileName);
    else
        inputStream = new FileInputStream(fileName);

    BufferedReader reader = new BufferedReader(
            new InputStreamReader(new BufferedInputStream(inputStream), "UTF-8"));

    String line;
    String[] splitedLine;
    List<ArrayList<WorkUnit>> activityLists =
    new ArrayList<ArrayList<WorkUnit>>();

   while ((line = reader.readLine()) != null) {

        ArrayList<WorkUnit> activity = new ArrayList<WorkUnit>();
        activity.add(new WorkUnit(activityId, workerId, duration));
        activityLists.add(activity);

    }
    reader.close();

    return activityLists;

}

我的想法是使用line.split（并且主要是我的问题）并在 for 循环中运行它，遗憾的是我失败了，如果你有任何想法如何在这或者不同的方式请帮忙。目标是获取每个activityId（行号从0开始）workerId（t之前的数字），为它们分配活动的持续时间（在文件中的t之后），并将它们添加到工作单位。

感谢任何帮助。是的，我是个菜鸟。

-------------------------------------------- - - -编辑 - - - - - - - - - - - - - - - - - - - - - - ------

为WorkUnit和splitLine逻辑添加了逻辑，该逻辑与其他文本文件一起使用，如下所示： enter image description here

其中“：”之前的数字是activityIds，第一个数字是workerIds，第二个是持续时间

公共类WorkUnit实现了Comparable {

int activityId;
int workerId;
int duration;

public WorkUnit(int activityId, int workerId, int duration) {

    super();
    this.activityId = activityId;
    this.workerId = workerId;
    this.duration = duration;

}

public int getActivityId() {
    return activityId;
}

public int getWorkerId() {
    return workerId;
}

public int getDuration() {
    return duration;
}

@Override
public String toString() {

    StringBuilder builder = new StringBuilder();
    if (workerId < 10) builder.append("  "); else builder.append(" ");
    builder.append(workerId);
    if (duration < 10) builder.append("  "); else builder.append(" ");
    builder.append(duration);

    return builder.toString();

}

@Override
public int compareTo(WorkUnit object) {

    if (this.activityId == object.getActivityId()
            && this.duration == object.getDuration()
            && this.workerId == object.getWorkerId())
        return 0;

    if (this.duration > object.getDuration()) return 1;
    return -1;

}

}

splitLine的逻辑：

   while ((line = reader.readLine()) != null) {

       ArrayList<WorkUnit> activity = new ArrayList<WorkUnit>();

       //1st place is activity id; always ascending order 0 to n
       splitedLine = line.split("(\\s)*(:)*\\s+");
       int activityId = Integer.parseInt(splitedLine[0]);
       for (int i = 1; i < splitedLine.length; i += 2) {
           int workerId = Integer.parseInt(splitedLine[i]);
           int duration = Integer.parseInt(splitedLine[i+1]);
           activity.add(new WorkUnit(activityId, workerId, duration));
       }

       acrivityLists.add(activity);

    }

Answer 1

Line.split是个好主意。实现看起来像这样：

String[] splitedLine = line.split(" ");

作为参数，split（）采用一个字符串来划分你的输入。然后，您可以使用以下方式访问元素：

splitedLine[0];  
splitedLine[1]; etc

Answer 2

在这里，我认为这就是你想要的，以便你的逻辑正常工作。

int activityNumber = 1;
while ((line = reader.readLine()) != null) {

   ArrayList<WorkUnit> activity = new ArrayList<WorkUnit>();

   //1st place is activity id; always ascending order 0 to n
   splitedLine = line.split(" ");
   // we know that value t will be the middle element.
   int len = splitedLine.length;
   for(int i=0; i<splitedLine.length/2; i++) {
       int workerId = Integer.parseInt(splitedLine[i]);
       int duration = Integer.parseInt(splitedLine[len - i - 1]);
       activity.add(new WorkUnit(activityNumber, workerId, duration));
   }

   activityNumber++;

   acrivityLists.add(activity);

}

希望这有帮助！

如何将数据从文本文件导入计划应用程序？

2 个答案: