将十六进制数据写入特定地址c＃的文件

Question

我需要帮助在c＃中的二进制文件中的地址0x0156处写入十六进制数据AB。 我使用的BinaryWriter提供了错误的数据00。

BinaryWriter bw = new BinaryWriter(File.OpenWrite(path));
bw.Write("AB");
bw.Dispose();

Answer 1

如果你需要在地址0x156写它，你需要先使用Seek方法移动它。您还需要编写字节值而不是字符串。

BinaryWriter bw = new BinaryWriter(File.OpenWrite(path));
bw.Seek(0x156,SeekOrigin.Begin);
bw.Write((byte)0xab);
bw.Dispose();

如果文件不存在，或者短于343个字节，则将使用0值填充，直到第342个字节。

如果你想从特定位置开始写一些字节，你可以这样做：

int StartLocation = 0x202;
int EndLocation = 0x30b;
byte ValueToWrite = 0xFF;
BinaryWriter bw = new BinaryWriter(File.OpenWrite(path));
bw.Seek(StartLocation,SeekOrigin.Begin);
for (int CurLocation = StartLocation; CurLocation <= EndLocation; CurLocation++)
  bw.Write(ValueToWrite);
bw.Dispose();

另一种方式是

int StartLocation = 0x202;
int EndLocation = 0x30b;
byte ValueToWrite = 0xFF;
byte [] ByteArray = new byte[EndLocation-StartLocation+1];
for (int i = 0; i < ByteArray.Length; i++)
  ByteArray[i] = ValueToWrite;
BinaryWriter bw = new BinaryWriter(File.OpenWrite(path));
bw.Seek(StartLocation,SeekOrigin.Begin);
bw.Write(ByteArray);
bw.Dispose();