在Ruby中迭代多个数组的最佳方式(性能方面的美观和高效)是什么? 假设我们有一个数组:
a=[x,y,z]
b=['a','b','c']
我想要这个:
x a
y b
z c
感谢。
答案 0 :(得分:6)
另一种方法是使用each_with_index
。快速基准测试显示,这比使用zip快一点。
a.each_with_index do |item, index|
puts item, b[index]
end
基准:
a = ["x","y","z"]
b = ["a","b","c"]
Benchmark.bm do |bm|
bm.report("ewi") do
10_000_000.times do
a.each_with_index do |item, index|
item_a = item
item_b = b[index]
end
end
end
bm.report("zip") do
10_000_000.times do
a.zip(b) do |items|
item_a = items[0]
item_b = items[1]
end
end
end
end
结果:
user system total real
ewi 7.890000 0.000000 7.890000 ( 7.887574)
zip 10.920000 0.010000 10.930000 ( 10.918568)
答案 1 :(得分:3)
数组对象上的zip
方法:
a.zip b do |items|
puts items[0], items[1]
end
答案 2 :(得分:2)
>> a=["x","y","z"]
=> ["x", "y", "z"]
>> b=["a","b","c"]
=> ["a", "b", "c"]
>> a.zip(b)
=> [["x", "a"], ["y", "b"], ["z", "c"]]
>>
答案 3 :(得分:1)
答案 4 :(得分:1)
我喜欢在使用Ruby迭代多个数组时使用转置。希望这会有所帮助。
bigarray = []
bigarray << array_1
bigarray << array_2
bigarray << array_3
variableName = bigarray.transpose
variableName.each do |item1,item2,item3|
# do stuff per item
# eg
puts "item1"
puts "item2"
puts "item3"
end