Question

尝试将PHP函数转换为Python，我是python的新手，tthats我试过的

Python - ＆gt;

def stopWords(text, stopwords):
  stopwords = map(to_lower(x),stopwords)
  pattern = '/[0-9\W]/'
  text = re.sub(pattern, ',', text)
  text_array = text.partition(',');
  text_array = map(to_lower(x), text_array);
  keywords = []
for term in text_array:
  if(term in stopwords):
     keywords.append(term)
 return filter(None, keywords)

stopwords = open('stop_words.txt','r').read()
text = "All words in the English language can be classified as one of the eight different parts of speech."
print(stopWords(text, stopwords))

PHP - ＆gt;

function stopWords($text, $stopwords)
    {

    // Remove line breaks and spaces from stopwords

    $stopwords = array_map(
    function ($x)
        {
        return trim(strtolower($x));
        }

    , $stopwords);

    // Replace all non-word chars with comma

    $pattern = '/[0-9\W]/';
    $text = preg_replace($pattern, ',', $text);

    // Create an array from $text

    $text_array = explode(",", $text);

    // remove whitespace and lowercase words in $text

    $text_array = array_map(
    function ($x)
        {
        return trim(strtolower($x));
        }

    , $text_array);
    foreach($text_array as $term)
        {
        if (!in_array($term, $stopwords))
            {
            $keywords[] = $term;
            }
        };
    return array_filter($keywords);
    }

$stopwords = file('stop_words.txt');


$stopwords = file('stop_words.txt');
$text = "All words in the English language can be classified as one of the eight different parts of speech.";
print_r(stopWords($text, $stopwords));

我在cmd上的python中收到错误： IndentationError：unindent与任何外部缩进级别都不匹配 Plz弄清楚我做错了什么，并在python

中“替换”

Answer 1

for应该缩进，当你编写它时，它似乎不在函数中。此外，最后一次返回不与for或函数对齐。

正确的缩进应如下所示：

def stopWords(text, stopwords):
  stopwords = map(to_lower(x),stopwords)
  pattern = '/[0-9\W]/'
  text = re.sub(pattern, ',', text)
  text_array = text.partition(',');
  text_array = map(to_lower(x), text_array);
  keywords = []
  for term in text_array:
    if(term in stopwords):
      keywords.append(term)
  return filter(None, keywords)

将PHP函数转换为Python 3

1 个答案: