Question

我已尝试过这几种方法，但我显然不太了解匹配和测试元素。

这第一位有效。它排除了整个EligibilityBenefit元素IF包含的子元素EligibilityorBenefitInformation等于＆＃39; I＆＃39;。

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output method="xml" encoding="utf-8" indent="yes"/>

    <!-- Identity template : copy all text nodes, elements and attributes -->   
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="EligibilityorBenefit[EligibilityorBenefitInformation='I']" />

  </xsl:stylesheet>

问题在于我尝试使选择更具限制性。

我已尝试过这些并且他们没有工作

match="EligibilityorBenefit[EligibilityorBenefitInformation='I' and ServiceTypeCode='35']"

match="EligibilityorBenefit[EligibilityorBenefitInformation='I'] and EligibilityorBenefit[ServiceTypeCode='35']"

我还试图像这样使用一场比赛

    <xsl:template match="EligibilityorBenefit">
      <xsl:choose>
      <xsl:when test="EligibilityorBenefitInformation='I' and ServiceTypeCode='35'">
      </xsl:when>
      <xsl:otherwise>
        <xsl:apply-templates select="@*|node()" />
      </xsl:otherwise>
      </xsl:choose>
    </xsl:template>

这就是我所拥有的

<Eligibility217>
  <Loop2110>
    <EligibilityorBenefit>
      <EligibilityorBenefitInformation>I</EligibilityorBenefitInformation>
      <CoverageLevelCode />
      <ServiceTypeCode>30</ServiceTypeCode>
      <InsuranceTypeCode>EP</InsuranceTypeCode>
    </EligibilityorBenefit>
  </Loop2110>
  <Loop2110>
    <EligibilityorBenefit>
      <EligibilityorBenefitInformation>A</EligibilityorBenefitInformation>
      <CoverageLevelCode>IND</CoverageLevelCode>
      <ServiceTypeCode>33</ServiceTypeCode>
    </EligibilityorBenefit>
    <EligibilityorBenefit>
      <EligibilityorBenefitInformation>I</EligibilityorBenefitInformation>
      <CoverageLevelCode>IND</CoverageLevelCode>
      <ServiceTypeCode>35</ServiceTypeCode>
    </EligibilityorBenefit>
    <Message>
      <MessageText>Specialist</MessageText>
    </Message>
    <Loop2115>
      <Information>
        <CodeListQualifierCode>ZZ</CodeListQualifierCode>
        <IndustryCode>11</IndustryCode>
      </Information>
    </Loop2115>
  </Loop2110>
</Eligibility217>

这就是我想要的

<Eligibility217>
  <Loop2110>
    <EligibilityorBenefit>
      <EligibilityorBenefitInformation>I</EligibilityorBenefitInformation>
      <CoverageLevelCode />
      <ServiceTypeCode>30</ServiceTypeCode>
      <InsuranceTypeCode>EP</InsuranceTypeCode>
    </EligibilityorBenefit>
  </Loop2110>
  <Loop2110>
    <EligibilityorBenefit>
      <EligibilityorBenefitInformation>A</EligibilityorBenefitInformation>
      <CoverageLevelCode>IND</CoverageLevelCode>
      <ServiceTypeCode>33</ServiceTypeCode>
    </EligibilityorBenefit>
    <Message>
      <MessageText>Specialist</MessageText>
    </Message>
    <Loop2115>
      <Information>
        <CodeListQualifierCode>ZZ</CodeListQualifierCode>
        <IndustryCode>11</IndustryCode>
      </Information>
    </Loop2115>
  </Loop2110>
</Eligibility217>

Answer 1

在我的例子中，我无意中发布了答案。

出于某种原因，我不相信它有效。再次检查后，我现在看到我从一开始就有了解决方案。

match="EligibilityorBenefit[EligibilityorBenefitInformation='I' and ServiceTypeCode='35']"

复制除具有两个子元素的节点以外的所有节点

1 个答案: