Question

List1 = [('100.20.300.400', 'varagu', 'success'), ('100.20.300.500', 'thinai', 'success')]
List2 = [('100.20.300.600', 'Ragi', 'Failed')]



 table = PrettyTable(['IP', 'Name', 'Result'])
for IP, Name, Result in succeed_ip.__getitem__():
    table.add_row([IP, Name, Result])
print table

Error: for IP, Name, Result in succeed_ip.__getitem__():
TypeError: __getitem__() takes exactly one argument (0 given)

我得到了预期的结果，我提到索引分别显示在表格中。而不是提到List1 索引，我可以得到相同的结果。我尝试了这个选项 table.add_row（List1），但我没有得到结果。我打算将来包含更多列表，所以我不想提及索引每次。请帮忙。谢谢!!!

Answer 1

List1 = [('100.20.300.400', 'varagu', 'success'), ('100.20.300.500', 'thinai', 'success')]
List2 = [('100.20.300.600', 'Ragi', 'Failed')]

table = PrettyTable(['IP', 'Name', 'Result'])
for IP, Name, Result in List1:
    table.add_row([IP, Name, Result])
print table

ftable = PrettyTable(['IP', 'Name', 'Result'])
for IP, Name, Result in List2:
    ftable.add_row([IP, Name, Result])
print ftable

Above script gave me the result for me. Issue is resolved. Thanks for the support.

Python漂亮的表

1 个答案: