我想创建一个允许用户输入SQL查询并将其转换为Pandas df的函数。到目前为止,我已尝试过以下内容:
def dataset():
raw_sql_query = input("Enter your SQL query: ")
sql_query = """" " + raw_sql_query + " """"
sql3 =
sql_query
df = pd.io.sql.read_sql(sql3, cnxn)
df.head()
产生错误:
File "<ipython-input-18-6b10c2bc776f>", line 4
sql_query = """" " + raw_sql_query + " """"
^
SyntaxError: EOL while scanning string literal
我也尝试过上面代码的几个相似版本,包括:
def dataset():
raw_sql_query = input("Enter your SQL query: ")
sql_query = """"" + raw_sql_query + """""
sql3 =
sql_query
df = pd.io.sql.read_sql(sql3, cnxn)
df.head()
导致以下错误:
File "<ipython-input-23-e501c9746878>", line 5
sql3 =
^
SyntaxError: invalid syntax
这样的功能可能吗?如果是这样,我将如何为此操作创建工作函数? 我读过的关于函数的所有文档仅包含打印“Hello World”或基本加法/减法/等内容的示例 - 因此不太有用。
编辑:
像这样使用pandas.read_sql_query
:
def dataset():
"""This functions allows you to input a SQL query and it will be transformed into a Pandas dataframe"""
raw_sql_query = input("Enter your SQL query: ")
sql_query = """"" + raw_sql_query + """""
sql3 = sql_query
df = pd.io.sql.read_sql(sql3, cnxn)
df.head()
这不会返回错误,但也不会返回预期的结果。它什么都不返回。
答案 0 :(得分:0)
我用
import pandas as pd
from sqlalchemy import create_engine
from sqlalchemy.sql import text as SQLtext
from sqlalchemy.sql import bindparam
engine = create_engine("postgres+psycopg2://"+settings.DBconn)
def readQuery(query, **params):
query = SQLtext(query)
for key, value in params.items():
query = query.bindparams(bindparam(key, value))
return(pd.read_sql(query, engine))
答案 1 :(得分:0)
我喜欢将sqlalchemy
与pandas.read_sql
结合使用的灵活性。这是我使用的代码:
import sqlalchemy as sa
def bindQuery(query, **params):
for key, value in params.items():
key = f":{key}"
if isinstance(value, str):
value = f"'{value}'"
query = query.replace(key, str(value))
query = query.replace("\n", " ").replace("\t", " ")
return query
def readQuery(query, engine, **params):
query = bindQuery(query, **params)
return pd.read_sql(query, engine)
因此,当我必须运行以下QUERY
QUERY = """
SELECT count(*)
FROM table
where id in :ids
"""
ids = (1, 2, 3)
df = readQuery(query=QUERY,
engine=my_engine,
ids=ids)