Question

我制作了一个包含4个不同孩子的抽象上传课程。

类UploadCoanyPic，UploadCompanyLogo和UploadUserPic是一对一关系，但UploadPostFile必须是多对一（一个帖子有很多上传的文件），我想使用alle抽象的函数上课，但我不能让多对一的关系奏效。这就是我现在所拥有的：

<?php

        namespace AppBundle\Entity\Upload;

        use Doctrine\ORM\Event\LifecycleEventArgs;
        use Doctrine\ORM\Mapping as ORM;
        use AppBundle\Util\Registry;
        use Symfony\Component\HttpFoundation\File\UploadedFile;

        /**
         * Abstract Class Upload
         *
         * @package AppBundle\Entity\Upload
         *
         * @ORM\MappedSuperclass()
         * @ORM\Entity(repositoryClass="AppBundle\Repository\Upload\UploadRepository")
         * @ORM\HasLifecycleCallbacks()
         * @ORM\Table(name="upload", indexes={
         *     @ORM\Index(name="idx_cat_id", columns={"category","foreign_id"})
         *      }
         * )
         * @ORM\InheritanceType("SINGLE_TABLE")
         * @ORM\DiscriminatorColumn(name="category", type="string")
         * @ORM\DiscriminatorMap({"company-pic" = "UploadCompanyPic", "user-pic" = "UploadUserPic", "company-logo" = "UploadCompanyLogo", "post-file" = "UploadPostFile"})
         */
        abstract class Upload
        {
            /**
             * @ORM\Id
             * @ORM\GeneratedValue(strategy="AUTO")
             * @ORM\Column(name="id", type="integer", length=255, nullable=false)
             */
            protected $id;


            protected $foreignId;
       /**
some more code
         * @return mixed
         */
        public function getForeignId()
        {
            return $this->foreignId;
        }

        /**
         * @param mixed $foreignId
         */
        public function setForeignId($foreignId)
        {
            $this->foreignId = $foreignId;
        }

UploadCompanyPic：

<?php

namespace AppBundle\Entity\Upload;

use Doctrine\ORM\Mapping as ORM;
use AppBundle\Entity\Upload\Upload as Upload;

/**
 *
 * @ORM\Entity
 *
 */

class UploadCompanyPic extends Upload
{

    protected $category="company-pic";

    /**
     * this is the foreign id of the mapped entity
     * @ORM\Column(name="foreign_id", type="integer", length=255, nullable=false)
     */
    protected $foreignId;

}

（上传CompanyLogo和UploadUserPic看起来一样）

<?php

namespace AppBundle\Entity\Upload;

use AppBundle\Entity\Blog\Post;
use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\ORM\Mapping as ORM;
use AppBundle\Entity\Upload\Upload as Upload;

/**
 *
 * @ORM\Entity
 *
 */

class UploadPostFile extends Upload
{

    protected $category="post-file";


    /**
     * ManyFiles have one Post
     * @ORM\ManyToOne(targetEntity="AppBundle\Entity\Blog\Post", inversedBy="files")
     * @ORM\JoinColumn(name="foreign_id", referencedColumnName="id")
     */
    protected $foreignId;

    /**
     * @return ArrayCollection
     */
    public function getForeignId()
    {
        return $this->foreignId;
    }

    /**
     * @param Post $foreignId
     */
    public function setForeignId($foreignId)
    {
        $this->foreignId = $foreignId;
    }



}

对我有什么建议吗？谢谢！

Answer 1

我的一位同事找到了答案：

/**
 * Abstract Class Upload
 *
 * @package AppBundle\Entity\Upload
 *
 * @ORM\MappedSuperclass()
 * @ORM\Entity(repositoryClass="AppBundle\Repository\Upload\UploadRepository")
 * @ORM\HasLifecycleCallbacks()
 * @ORM\Table(name="upload", indexes={
 *     @ORM\Index(name="idx_cat_id", columns={"category","foreign_id"})
 *      }
 * )
 * @ORM\InheritanceType("SINGLE_TABLE")
 * @ORM\DiscriminatorColumn(name="category", type="string")
 * @ORM\DiscriminatorMap({"company-pic" = "UploadCompanyPic", "user-pic" = "UploadUserPic", "company-logo" = "UploadCompanyLogo", "post-file" = "UploadPostFile", "partner-logo" = "UploadPartnerLogo"})
 */
abstract class Upload

继承映射和多对一关系

1 个答案: