Question

我有疑问：

$listings = Yii::app()->db->createCommand('SELECT * FROM listings')->where(['or like','c_sales_stage',['Needs Refresh','Active']])->andWhere('c_listing_featured_c = 1')->queryAll();

即使c_listing_featured_c为0，也会返回所有列表。我做错了什么？

由于

Answer 1

正如documentation所说：

注意：“查询”构建器不能用于修改指定为SQL语句的现有查询。例如，以下代码无效：

$command = Yii::app()->db->createCommand('SELECT * FROM tbl_user');
// the following line will NOT append WHERE clause to the above SQL
$command->where('id=:id', array(':id'=>$id));

要解决您的问题，请从createCommand()函数中删除参数并在链中添加from()：

$listings = Yii::app()->db->createCommand()
   ->from('listings')
   //->where()       //here your where condition
   ->andWhere('c_listing_featured_c = 1')
   ->queryAll();

Yii 1查询返回错误数据

1 个答案: