Question

我试图将列表值从一个列表插入到另一个列表中，但是按照特定顺序，其中date [0]输入了文本[1]，日期[1]输入了文本[3]，依此类推。

dates=['21/11/2044', '31/12/2018', '23/9/3000', '25/12/2007']

text=['What are dates? ', ', is an example.\n', ', is another format as
well.\n', ', also exists, but is a bit ludicrous\n', ', are examples but more commonly used']

我试过这个方法：

for j in range(len(text)):
  for i in range(len(dates)):
   text.insert(int((j*2)+1), dates[i])

这是结果，这是不正确的：

['What are dates? ', '25/12/2007', '23/9/3000', '25/12/2007', '23/9/3000',
'25/12/2007', '23/9/3000', '25/12/2007', '23/9/3000', '25/12/2007',
'23/9/3000', '31/12/2018', '21/11/2044', '31/12/2018', '21/11/2044',
'31/12/2018', '21/11/2044', '31/12/2018', '21/11/2044', '31/12/2018',
'21/11/2044', ', is an example.\n', ', is another format as well.\n', ',
also exists, but is a bit ludicrous\n', ', are examples but more commonly used']

我试图找回一个如下所示的列表：

['What are dates? ','21/11/2044', 'is an example.\n','31/12/2018', ', is
another format as well.\n','23/9/3000', ', also exists, but is a bit
ludicrous\n', '25/12/2007',', are examples but more commonly used']

有没有办法按照我想要的方式将日期[i]插入文本[2 * j + 1]？我是否应该使用for循环，或者是否有其他方式而不在日期中列出所有内容？

Answer 1

实现这一目标的一种更简单的方法是在Python 3.x中使用itertools.zip_longest（或在Python 2.x中使用izip_longest）：

>>> from itertools import zip_longest # for Python 3.x

>>> # For Python 2.x
>>> # from itertools import izip_longest

>>> dates=['21/11/2044', '31/12/2018', '23/9/3000', '25/12/2007']
>>> text=['What are dates? ', ', is an example.\n', ', is another format as well.\n', ', also exists, but is a bit ludicrous\n', ', are examples but more commonly used']

>>> [w for x in zip_longest(text, dates, fillvalue='') for w in x if w]
['What are dates? ', '21/11/2044', ', is an example.\n', '31/12/2018', ', is another format as well.\n', '23/9/3000', ', also exists, but is a bit ludicrous\n', '25/12/2007', ', are examples but more commonly used']

您的代码存在的问题是您有嵌套的for循环，这就是为什么j的每个索引都会添加dates的所有值。

Answer 2

对于您希望在其他所有元素中拟合日期的具体示例，您可以使用zip：

parts = zip(['a', 'b', 'c', 'd'], ['d1', 'd2', 'd3'])
text = [x for y in parts for x in y]
# ['a', 'd1', 'b', 'd2', 'c', 'd3']

您可能需要使用itertools.izip_longest和/或在列表之间处理不相等的长度，否则您会看到如上所述的结果，其中'd'不在最后。第二行是丑陋的列表理解魔术，以压缩列表列表。

Answer 3

您可以使用：

result = [ ]
for x in enumerate(dates, text):
   result.append(dates[x]).append(text[x])

Answer 4

双循环是这里的问题;只需使用单个for循环，如

for i in range(len(dates)):
    text.insert(int((i*2)+1), dates[i])

应该这样做。

但是，如果您计划将第二个列表作为字符串结束，则使用.format可能更简单，如

text = 'Date with one format is {} and date with another format is {}.'.format(*dates)

会给你

'Date with one format is 21/11/2044 and date with another format is 31/12/2018.'

Answer 5

也许它不是最优雅的版本，但这可以作为例如：

from itertools import zip_longest


dates=['21/11/2044', '31/12/2018', '23/9/3000', '25/12/2007']

text=['What are dates? ', ', is an example.\n', ', is another format as well.\n', ', also exists, but is a bit ludicrous\n', ', are examples but more commonly used']


l3 = list()
for i, j in zip_longest(text, dates, fillvalue=None):
    if i is not None:
        l3.append(i)
    if j is not None:
        l3.append(j)

print(l3)

来自标准itertools模块的

zip_longest将2个不均匀长度的列表拉在一起，并用“fillvalue”填充缺失值。如果你只丢弃那个fillvalue，你就可以去了。

Answer 6

一个非常容易理解的简单解决方案

counter = 0
while counter < len(dates):
    text.insert(counter + counter + 1, dates[counter])
    counter += 1

基本上，.insert()用于附加到特定位置的列表。

在Python中以特定顺序将列表值从列表插入到另一个列表中

6 个答案: