Question

我是一名新的程序员，由于我是学生，我对异常处理非常缺乏经验。我正在编写一个程序，让用户可以安排从1到6点钟开始的约会。如果用户输入除整数之外的任何值，我希望程序告诉用户他/她的输入有错误，并且应该将其更改为整数值，而不是double，String，char等。是我的代码如下：

boolean created = false;
while (!created) {
    // Asks when you want your appointment
    System.out.println("When would you like your appointment?");
    int userTime = input.nextInt();

    try {
        /**
        * I really do not know what to put in here. If the user inputs things like
        * letters and symbols and doubles or floats, etc. I want the program to send a
        * message to the user saying that an integer value must enter an integer.
        */
        userTime = input.nextInt();
    } catch (InputMismatchException ime) {
        System.out.println("Error! Please enter an integer from 1 to 6. Letters and symbols are not allowed");
    }   

    /*
    * Checks if the time value is either not in range and not taken- than lets you
    * pass on to create the appointment and add it into the array
    */

    if (userTime < 1 || userTime > 6) {
        System.out.println("Time value not in range");
    } else if (appointments[userTime] != null) {
        System.out.println("Time already taken");
    } else {
        // Adds username into array of Appointments
        created = true;
        apTotal++;
        appointments[userTime] = name;
    }
}

另外，顺便说一下 - 我不完全确定它是否实际上是一个inputMisMatch异常或其他东西，但如果它不是，请告诉我，因为我是初学者。谢谢大家！

Answer 1

所以从你的代码片段我猜你正在使用某些类型的扫描仪/ BufferedReader设置。检查整数输入的好方法是使用它们 “Integer.parseInt（）”函数（参见：https://docs.oracle.com/javase/7/docs/api/java/lang/Integer.html#parseInt(java.lang.String)）如果这不能将输入解析为有效整数，它将抛出一个“NumberFormatException”，然后您可以捕获并处理它！希望这有帮助！

Java-处理inputMisMatch异常

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