我需要一些帮助来加入我目前的表格。
离开，加时赛和名册的日期，员工ID需要匹配
注意：ShiftDuration设置为默认值= 8.25
注意：当员工申请休假和加班时，请假和加班表只有条目。
Employee
EmplyeeeID | Username | Password | GivenName | FamilyName | TeamID | ContactNo | StaffType
------------------------------------------------------------------------------------------
123 123 abc John Snow 1 999 1
1234 1234 abcd Jack Waller 2 223 1
12345 12345 abcde Ali Saw 1 123 1
123456 123456 abcdef Peter Peter 2 223 1
1234567 1234567 abcdeg Bryan Peter 1 333 1
Roster
Duty_ID | EmployeeID | Date | ShiftType | ShiftDuration
--------------------------------------------------------------------
2 123 2018-05-05 1 8.25
4 1234 2018-05-04 1 8.25
5 12345 2018-05-05 1 8.25
7 123456 2018-05-04 1 8.25
8 1234567 2018-05-05 1 8.25
Overtime
OTID | EmployeeID | Date | OT_Duration | OT_Reason
------------------------------------------------------------
2 1234 2018-05-04 2 Cover Duty
Leave
LeaveID | EmployeeID | Date | Duration_Off | Reason
----------------------------------------------------------
3 123 2018-05-05 2 NIL
IdealTable (Via Query)
Date | EmployeeID | GivenName | FamilyName | TeamID | ShiftType | ShiftDuration | Duration_Off | OT_Duration | Total_Hours
---------------------------------------------------------------------------------------------------------------------------------
2018-05-05 123 John Snow 1 1 8.25 2 0 6.25
2018-05-04 1234 Jack Waller 1 1 8.25 0 2 10.25
2018-05-05 12345 Ali Saw 1 1 8.25 0 0 8.25
2018-05-04 123456 Peter Peter 1 1 8.25 0 0 8.25
2018-05-05 1234567 Bryan Peter 1 1 8.25 2 0 8.25
我有4张桌子，他们是员工，休假，加班，名册
Employee
-EmployeeID (PK)
-Username
-Password
-GivenName
-FamilyName
-TeamID
-ContactNo
-StaffType
Leave
-LeaveID (PK)
-EmployeeID (FK)
-Date
-Duration_Off
-Reason
Overtime
-OTID (PK)
-EmployeeID (FK)
-Date
-OT_Duation
-OT_Reason
Roster
-DutyID (PK)
-EmployeeID (FK)
-Date
-ShiftType
-Shift Duration (Default Value = 8.25)
我要做的是使用Query
加入这4个表中的数据Ideal Table
-Date (From Leave, Overtime and Roster Table)
-EmployeeID (Employee Table)
-GivenName (Employee Table)
-FamilyName (Employee Table)
-TeamID (Employee Table)
-ShiftType (Roster Table)
-ShiftDuration (Roster Table)
-Duration_Off (Leave Table)
-OT_Duration (Overtime Table)
-Total_Hours (Calculation from joint table [(ShiftDuration + OT_Duration) - Duration_Off]
My database diagram design请忽略TimeData表，因为我最初想使用TimeData表来实现IdealTable
我当前的查询
USE [SMRT Dashboard]
GO
;With Dates
AS
(
SELECT [Date] FROM dbo.Roster
UNION
SELECT [Date] FROM dbo.Leave
UNION
SELECT [Date] FROM dbo.Overtime
),
Work_Matrix
AS
(
SELECT EmployeeID,[Date],ShiftType,ShiftDuration,CAST(NULL AS Decimal(30,2)) AS Duration_Off,CAST(NULL AS Decimal(30,2)) AS OT_Duration
FROM dbo.Roster
UNION ALL
SELECT EmployeeID,[Date], NULL, NULL,Duration_Off
FROM dbo.Leave
UNION ALL
SELECT EmployeeID,[Date],NULL,NULL,NULL,OT_Duration
FROM dbo.Overtime
)
SELECT d.[Date],
e.EmployeeID,
e.GivenName,
e.FamilyName,
e.TeamID,
w.ShiftType,
w.ShiftDuration,
w.Duration_Off,
w.OT_Duration,
w.Total_Hours
FROM Dates d
INNER JOIN
(
SELECT EmployeeID,
[Date],
MAX(ShiftType) AS ShiftType,
SUM(ShiftDuration) AS ShiftDuration,
SUM(Duration_Off) AS Duration_Off,
SUM(OT_Duration) AS OT_Duration,
SUM(ShiftDuration) + SUM(OT_Duration) - SUM(Duration_Off) AS Total_Hours
FROM Work_Matrix
GROUP BY EmployeeID,
[Date]
)w
ON d.[Date] = w.[Date]
JOIN dbo.Employee e
ON e.EmployeeID = w.EmployeeID
当前错误：
Msg 205, Level 16, State 1, Line 4
All queries combined using a UNION, INTERSECT or EXCEPT operator must have an equal number of expressions in their target lists.
答案 0 :(得分：0)
我没有测试过这个，但你现在可以检查一下。希望你的问题能够得到解决。
SELECT
a.EmployeeID,
a.GivenName,
a.FamilyName,
a.TeamID,
d.ShiftType,
d.ShiftDuration,
b.Duration_Off,
c.OT_Duration,
b.Date,
(d.ShiftDuration + c.OT_Duration) - b.Duration_Off as Total_Hours
FROM Employee a
INNER JOIN Roster d ON a.EmployeeID = d.EmployeeID
LEFT JOIN Leave b ON a.EmployeeID = b.EmployeeID
LEFT JOIN Overtime c ON a.EmployeeID = c.EmployeeID
我假设Date在所有三个表中都是相同的（离开，加班和名册表）
答案 1 :(得分：0)
尝试此查询：
select
l.Date,
o.Date,
r.Date,
e.EmployeeID,
e.GivenName,
e.FamilyName,
e.TeamID,
r.ShiftType,
r.ShiftDuration,
l.Duration_Off,
o.OT_Duration,
((r.ShiftDuration+o.OT_Duration)-l.Duration_Off) as Total_Hours
FROM Employee e
INNER JOIN Leave l ON e.EmployeeID = l.EmployeeID
INNER JOIN Overtime o ON e.EmployeeID = o.EmployeeID
INNER JOIN Roster r ON r.EmployeeID = r.EmployeeID;
答案 2 :(得分：0)
试试此查询！您将获得正确的输出。
SELECT
e.EmployeeID AS 'Emp ID',
e.GivenName AS 'Emp Name',
l.Date AS Date,
e.FamilyName AS 'Family Name',
e.TeamID AS 'Team ID',
r.ShiftType AS 'Shift Type',
r.ShiftDuration AS 'Shift Duration',
l.Duration_Off AS 'Duration Off',
o.OT_Duration AS 'OT Duration',
(r.ShiftDuration + o.OT_Duration) - l.Duration_Off as 'Total Hours'
FROM
Employee e,
Leave l,
Overtime o,
Roster r
WHERE
e.EmployeeID = l.EmployeeID
AND
e.EmployeeID = o.EmployeeID
AND
e.EmployeeID = r.EmployeeID
答案 3 :(得分：0)
我认为这里的问题是员工可能有休假，可能有加班，或者两者都没有。通过使用INNER JOIN，您可以将该组员工过滤为具有“离开”和“名册”的员工，并加班。
我创建了一个SqlFiddle，其中包含您提供的数据（请参阅here），它可以让您更接近。
SELECT
COALESCE(r.Date, o.Date, l.Date) as Date,
e.EmployeeID,
e.GivenName,
e.FamilyName,
e.TeamID,
r.ShiftType,
r.ShiftDuration,
IFNULL(l.Duration_Off, 0) as Duration_Off,
IFNULL(o.OT_Duration, 0) as OT_Duration,
r.ShiftDuration + IFNULL(o.OT_Duration, 0) - IFNULL(l.Duration_Off, 0) as Total_Hours
FROM Employee e
INNER JOIN Roster r on
e.EmployeeID = r.EmployeeID
LEFT JOIN Overtime o on
e.EmployeeID = o.EmployeeID
LEFT JOIN `Leave` l on
e.EmployeeID = l.EmployeeID
这个查询无法解决几个cavaets：
如果您使用TimeData，这将变得更加容易（假设每个员工每个日期有一条记录）：
SELECT
COALESCE(r.Date, o.Date, l.Date) as Date,
e.EmployeeID,
e.GivenName,
e.FamilyName,
e.TeamID,
r.ShiftType,
IFNULL(r.ShiftDuration, 0) as ShiftDuration,
IFNULL(l.Duration_Off, 0) as Duration_Off,
IFNULL(o.OT_Duration, 0) as OT_Duration,
IFNULL(r.ShiftDuration, 0) + IFNULL(o.OT_Duration, 0) - IFNULL(l.Duration_Off, 0) as Total_Hours
from TimeData t
INNER JOIN Employee e on
t.EmployeeID = e.EmployeeID
LEFT JOIN Roster r on
t.Duty_ID = r.Duty_ID
LEFT JOIN Overtime o on
t.OTID = o.OTID
LEFT JOIN `Leave` l on
t.LeaveID = l.LeaveID
可以找到示例SqlFiddle here