Question

我制作了一个文本文件：

52 57 63 69 71 78 82 84 95 96

我需要用相应的数字垂直打印，包括所有数字的总和，但我只想出这个：

with open("numbers.txt", "r") as f:
    a = [int(n) for line in f.readlines() for n in line.split()]
    print a
    print("\n")

with open("numbers.txt", "r") as f:
    for l in f:
        print(sum([int(a) for a in l.split()]))

Answer 1

你很亲密。试试这个：

with open('numbers.txt', 'r') as fl:
    text = fl.read()

numbers = [int(n) for n in text.split()]

answer = sum(numbers)

for n in numbers:
    print(n)
print(answer)

这会产生：

Answer 2

您不需要两次读取文件

with open("numbers.txt", "r") as f:
  for line in f:
    a = line().split()
    for x in a
        print(x)
    print(sum(int(x) for x in a))

Answer 3

代码中的一些更改：

with open("numbers.txt", "r") as f:
    a = [int(n) for line in f.readlines() for n in line.split()]
    for i in a:
        print(i)
    print("Sum: ", sum(a))

输出：

Answer 4

如果文本文件只有一行，您可以使用f.readline()阅读，如下所示：

with open('test.txt') as f:
    nums = [int(n) for n in f.readline().split()]

for num in nums:
    print(num)

print()
print(sum(nums))

52
57
63
69
71
78
82
84
95
96

747
>>>

我无法让我的程序垂直打印我的文本文件

4 个答案: