Question

我正在尝试使用Flask-SQLAclchemy和Postgres为用户类模型创建数据库表。

我的模特课。

from app import db
class User(db.Model):
    __tablename__ = 'users'
    id = db.Column(db.Integer, primary_key=True)
    username = db.Column(db.String(70), index=True, nullable=False)
    email = db.Column(db.String(70), index=True, unique=True, nullable=False)
    password = db.Column(db.String(128))

我的应用初始化。

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
app = Flask(__name__)
app.config.from_object('app.instance.config.DevelopmentConfig')
app.config['SQLALCHEMY_DATABASE_URI'] = 'postgresql://postgres:RandomPass@localhost/BrightEventDb'
SQLALCHEMY_TRACK_MODIFICATIONS = True
db = SQLAlchemy(app)

会记录以下信息。

2018-01-06 11:53:09,978 INFO sqlalchemy.engine.base.Engine select version()
2018-01-06 11:53:09,979 INFO sqlalchemy.engine.base.Engine {}
2018-01-06 11:53:09,982 INFO sqlalchemy.engine.base.Engine select current_schema()
2018-01-06 11:53:09,982 INFO sqlalchemy.engine.base.Engine {}
2018-01-06 11:53:09,984 INFO sqlalchemy.engine.base.Engine SELECT CAST('test plain returns' AS VARCHAR(60)) AS anon_1
2018-01-06 11:53:09,985 INFO sqlalchemy.engine.base.Engine {}
2018-01-06 11:53:09,986 INFO sqlalchemy.engine.base.Engine SELECT CAST('test unicode returns' AS VARCHAR(60)) AS anon_1
2018-01-06 11:53:09,987 INFO sqlalchemy.engine.base.Engine {}
2018-01-06 11:53:09,990 INFO sqlalchemy.engine.base.Engine show standard_conforming_strings
2018-01-06 11:53:09,991 INFO sqlalchemy.engine.base.Engine {}

Answer 1

正如提及的评论中的某些人您未将模型导入应用初始化模块。您可以按照以下方式执行此操作

from models import User

Answer 2

如果您正在关注烧瓶快速启动最小应用程序，则该命令默认工作，因为User类与db实例位于同一位置。但是，在您的情况下，您必须将评论User中提到的from models import User课程导入应用初始化

db.create_all（）不在Flask-SQLAclchemy中创建表

2 个答案: