Question

这很奇怪。我有这个输出：

printf

这是我的代码：

converting sass to css...
[18:36:00] gulp-debug: src/app/app.component.scss
[18:36:00] gulp-debug: src/app/pages/about/about.component.scss
[18:36:00] gulp-debug: src/app/pages/contact/contact.component.scss
[18:36:00] gulp-debug: src/app/pages/home/home.component.scss
[18:36:00] gulp-debug: src/app/pages/home/components/control-panel/control-panel.component.scss
[18:36:00] gulp-debug: 5 items
notify clients of css change
change /Users/alexamil/WebstormProjects/oresoftware/sumanjs/suman-chrome-extension/app/app.component.css
change /Users/alexamil/WebstormProjects/oresoftware/sumanjs/suman-chrome-extension/app/pages/home/home.component.css
change /Users/alexamil/WebstormProjects/oresoftware/sumanjs/suman-chrome-extension/app/pages/home/components/control-panel/control-panel.component.css
change /Users/alexamil/WebstormProjects/oresoftware/sumanjs/suman-chrome-extension/app/pages/about/about.component.css
change /Users/alexamil/WebstormProjects/oresoftware/sumanjs/suman-chrome-extension/app/pages/contact/contact.component.css

从日志中看起来文件正在写出来，但是从我的编辑器来看，文件系统中似乎没有任何新的.css文件，只有.scss文件。任何人都知道可能出错了什么？

Answer 1

仅在使用动态src的情况下，并且您想要各自相同的dest（如src中所接收的），则可以使用以下

示例假设我们有一个scss文件数组：

var gulp = require('gulp');
var sass = require('gulp-sass');

var scssArr = [
    'src/asdf/test2.scss',
    'src/qwerty/test1.scss'
];


function runSASS(cb) {
    scssArr.forEach(function(p){
        gulp.src(p, {base:'.'})
        .pipe(sass({outputStyle: 'compressed'}))//outputStyle is optional or simply sass()
        .pipe(gulp.dest('.')); //if othe folder including src path then use '/folder-name' instead of '.', so output path '/folder-name/{src-received-path}'
    })
    cb();
}

exports.runSASS = runSASS; // gulp runSASS

运行命令gulp runSASS，将创建以下文件：

src / asdf / test2.css

src / qwerty / test1.css

快乐编码..

gulp.src没有写出目标文件

1 个答案: