我需要创建一个SQL查询来执行此操作:
我试过这个,但它不起作用(Where Condition):
SELECT S1.TotalMontantESP, S2.TotalMontantCHQ, S3.TotalMontantLCN, S4.NombreFactures, S5.PremièreDate, S5.DernièreDate, S5.PremièreFacture, S5.DernièreFacture, S5.NumeroCaisse
FROM
(SELECT sum(Montant) As TotalMontantESP FROM (SELECT TOP 6 Montant FROM Paiements_17_18) WHERE Type_Reglement = "Espèces") As P) As S1,
(SELECT sum(Montant) As TotalMontantCHQ FROM (SELECT TOP 6 Montant FROM Paiements_17_18) WHERE Type_Reglement = "Chèque") As P) As S2,
(SELECT sum(Montant) As TotalMontantLCN FROM (SELECT TOP 6 Montant FROM Paiements_17_18) WHERE Type_Reglement = "LCN") As P) As S3,
(SELECT Count(N_Facture) AS NombreFactures FROM (SELECT DISTINCT N_Facture FROM (SELECT TOP 6 N_Facture FROM Paiements_17_18) AS P1) AS P2) AS S4,
(SELECT Min([Date_Reglement]) AS PremièreDate, Max([Date_Reglement]) AS DernièreDate, Min([N_Facture]) AS PremièreFacture, Max([N_Facture]) AS DernièreFacture, Max([N_Caisse]) AS NumeroCaisse
FROM (SELECT TOP 6 Paiements_17_18.* FROM Paiements_17_18) AS P3) AS S5;
答案 0 :(得分:0)
我建议:
SELECT sum(Montant)
FROM (SELECT TOP 6 p.*
FROM Paiements_17_18 as p
ORDER BY ID_Paiement DESC
) as p
WHERE T.Type_Reglement = "Espèces";
有点难以理解您的查询逻辑,但我非常确定您在获取where
之后正在执行sum()
。< / p>