Question

我正在尝试创建密码生成器。我已经成功创建了一个功能代码，但它不断显示如何生成密码，而不是只显示如下所示的三行：

这是我的代码：

def Generate(): #menu function, Generates a password
    global password
    print("Generating...")

    chars = "abcdefghijklmnopqrstuvwxyz01234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ!@#$%^&*()?" #These are the avaliable characters available to the password

    length = input("password length?") #asks for how long the user wants their password

    if int(length) < 25: #Doesn't allow the code to print over 26 characters        

        length = int(length)


        for p in range(3):

            password = " "

            for c in range(length): #for loop which 

                password += random.choice(chars) #randomly choses characters at random to create the password

                print(password)

    else:
       print ("The password can only be between 8-24 characterss long")
       Generate ()

这是我运行的程序：

Generating...
password length?14
*
*C
*CD
*CDb
*CDbF
*CDbFA
*CDbFAi
*CDbFAiK
*CDbFAiKk
*CDbFAiKkA
*CDbFAiKkAa
*CDbFAiKkAa9
*CDbFAiKkAa9m
*CDbFAiKkAa9mr
7
7Y
7Ys
7Ysy
7Ysyj
7Ysyjj
7Ysyjj2
7Ysyjj28
7Ysyjj28C
7Ysyjj28Ch
7Ysyjj28Chq
7Ysyjj28Chqk
7Ysyjj28Chqk(
7Ysyjj28Chqk(k
E
E%
E%C
E%C8
E%C8(
E%C8(w
E%C8(w7
E%C8(w7M
E%C8(w7Mj
E%C8(w7MjP
E%C8(w7MjPO
E%C8(w7MjPOz
E%C8(w7MjPOzx
E%C8(w7MjPOzxx

你能帮我把代码输出三个字吗？

非常感谢。

Answer 1

您错误地缩进了这个：

for p in range(3):

    password = " "

    for c in range(length):#for loop which 

        password += random.choice(chars)#randomly choses characters at random to create the password

        print(password)

应该是这样的：

    for p in range(3):

        password = " "

        for c in range(length):#for loop which

            password += random.choice(chars)#randomly choses characters at random to create the password

        print(password)

通过将print语句放在第一个循环中，它只会在p的每次迭代结束时执行，而不是每次迭代c都执行。

Answer 2

我们可以帮助你的事情远远超过你实际要求的东西！我会根据您的要求编写相同的代码（假设我没问题）并附上评论。

import random

def generate_password(): #menu function, Generates a password
    # global password           # NOT NEEDED BUT I"M ASSUMING THINGS HERE
    print("Generating...")

    chars = "abcdefghijklmnopqrstuvwxyz01234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ!@#$%^&*()?"#These are the avaliable characters available to the password

    length = int(input("password length?")) #asks for how long the user wants their password

    if length <= 26: #Doesn't allow the code to print over 26 characters -> THIS SHOULD BE LESS THAN OR EQUAL TO 26 BC YOU SAID OVER 26 CHARS
        for p in range(3):
            password = " "        # EMPTY STRING.. PYTHON WOULDN'T MIND
            for c in range(length): #for loop which
                password += random.choice(chars) #randomly choses characters at random to create the password -> CONCATENATION HERE.. WE LOVE IT.
            print(password)  # THIS WAS OUT OF PLACE.
    else:
       print ("The password can only be between 8-24 characterss long")
       generate_password ()     # PERFECT!

generate_password()

现在，在我带来一些好的代码之后我就无法在晚上睡觉了，我知道如果我按照自己的方式行事，我可以提高它。

import random
import string


def generate_password(): #menu function, Generates a password
    print("Generating...")
    try:
        length = int(input("password length?")) #asks for how long the user wants their password
        if 8 <= length < 25:  # Doesn't allow the code to print over 26 characters -> THIS SHOULD BE LESS THAN OR EQUAL TO 26 BC YOU SAID OVER 26 CHARS
            password = ''.join(random.choice(string.ascii_letters + string.digits + "!@#$%^&*()?") for _ in range(length))    # throw away variable caution here!
            print(password)
        else:
            print("The password can only be between 8-24 characterss long")
            generate_password()  # PERFECT!
    except Exception as e:  # Do some homework on what kind of exception(s) you would like to catch ( like ValueError)
        print(e)
        pass                # Don't just pass it. Do something here depending on the Exception

generate_password()

Answer 3

你的内部循环中用于字符选择的print语句是这里的罪魁祸首，只需向左推一个缩进它就可以了。

for c in range(length): #for loop which 

    password += random.choice(chars) #randomly choses characters at random to create the password

print(password)

将其保留在for p in range(3):循环中。

Answer 4

当然，只需将打印件移出循环：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:id="@+id/activity_main"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context="org.komamitsu.android_ocrsample.MainActivity">


    <Button
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/choose_from_gallery"
        android:id="@+id/choose_from_gallery"
        tools:context=".MainActivity"
        android:layout_marginTop="23dp"
        android:layout_alignParentTop="true"
        android:layout_centerHorizontal="true" />

    <Button
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/take_a_photo"
        android:id="@+id/take_a_photo"
        tools:context=".MainActivity"
        android:layout_marginTop="11dp"
        android:layout_below="@+id/choose_from_gallery"
        android:layout_centerHorizontal="true" />


    <TextView
        android:text=""
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:id="@+id/detected_text"
        android:layout_alignParentBottom="true"
        android:layout_below="@+id/take_a_photo"
        android:layout_margin="25dp"
        android:layout_centerHorizontal="true"
        android:background="#EEEEEE"
        android:scrollbars="vertical" />

</RelativeLayout>

你也可以考虑这个：

for c in range(length):
    password += random.choice(chars)
print(password)

重复密码

4 个答案: